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Molodets [167]
2 years ago
7

39. Analyze What subscripts would you most likely use if

Chemistry
1 answer:
Igoryamba2 years ago
4 0

Based on their valencies, the subscripts of the ionic compounds formed will be:

  • 1 and 1
  • 2 and 1
  • 1 and 2
  • 2 and 2

<h3>What subscripts would you most likely use if the following substances formed an ionic compound?</h3>

A. An alkali metal and a halogen.

An alkali metal and a halogen both have valencies of one.

Therefore the subscripts would be 1.

B. An alkali metal and a non-metal from group 16.

An alkali metal has a valency of 1 and a group 16 non-metal has a valency of 2.

By exchange of valencies, the subscript would be 2 and 1.

C. An alkaline earth metal and a halogen.

An alkaline earth metal has a valency of 2 and a halogen has a valency of 1.

By exchange of valencies, the subscripts would be 1 and 2.

D. An alkaline earth metal and a non-metal from group 16.

An alkaline earth metal has a valency of 2 and a non-metal from group 16 has a valency of 2.

By exchange of valencies, the subscripts would be 2 and 2.

Therefore, the subscripts of the ionic compounds formed will be:

  • 1 and 1
  • 2 and 1
  • 1 and 2
  • 2 and 2

Learn more about about valency at: brainly.com/question/2284519

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Apply this theory onto salts.
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"in which direction does this reaction tend to proceed under standard conditions?"
Black_prince [1.1K]

Answer : Right

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6 0
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Read 2 more answers
Values for the molar mass of nitrogen, oxygen, and nitrogen dioxide
CaHeK987 [17]

Answer:

n=N/Na

n =  \frac{8.23 \times {10}^{22} }{6.02  \times {10}^{23} }  = 0.1367 \: mol

answer: 0.14 mol

Explanation:

5 0
3 years ago
***BRAINLIEST ASNWERRR***<br>How many grams are in 34.2 moles of Lithium (Li)?​
Step2247 [10]

Mass of Li = 237.38 g

<h3>Further explanation</h3>

The mole itself is the number of particles contained in a substance amounting to 6.02.10²³  

\large {\boxed {\boxed {\bold {mol = \frac {mass} {molar \: mass}}}}

<h3>Known</h3>

Moles of Li = 34.2

Molar mass(MW) of Li = 6.941 g/mol

then mass of Lithium (Li) :

\tt mol=\dfrac{mass}{MW}\\\\mass=mol\times MW\\\\mass=34.2\times 6,941~g/mol\\\\mass=\boxed{\bold{237.38~g}}

3 0
3 years ago
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