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yan [13]
2 years ago
9

Can you please help me​

Physics
1 answer:
g100num [7]2 years ago
7 0

Answer: Hello Miko here to help!

Explanation: The answer is c!

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A rock is dropped from a height of 3.4 m. How much time does it take to hit
siniylev [52]
Answer: 33.32 s

Explanation: gravity =9.8m/s2 which means that 3.4mx9.8m/s2=33.32s

I hope this helped ! Sorry if it’s wrong :)
6 0
3 years ago
Why should a physical quantity be measured?​
Natasha_Volkova [10]

Answer:

It allows us to understand nature much more deeply than does qualitative description alone.

Explanation:

Without explaining the measurements, a quantity cannot always be measured.

Hope this helped, and please mark as Brainliest :)

8 0
3 years ago
Three wires meet at a junction. wire 1 has a current of 0.40 aa into the junction. the current of wire 2 is 0.73 aa out of the j
Mnenie [13.5K]

The magnitude of the current in wire 3 is (I₃)= 0.33A

<h3>How to calculate the value of the magnitude of the current in wire 3 ?</h3>

To calculate the magnitude of the current in wire 3 we are using the Kirchhoff’s current law,

I₁ + I₂ + I₃ = 0

Where we are given,

I₁ = current in wire 1

=0.40 A.

I₂ = current in wire 2

= -0.73 A.

We have to calculate the magnitude of the current in wire 3, I₃

Now we put the known values in above equation, we get,

I₁ + I₂ + I₃ = 0

Or, I₃ = -.(I₁ + I₂)

Or, I₃ = -.(0.40 - 0.73)

Or, I₃ = 0.33 A

From the above calculation, we can conclude that the current in wire 3 is  I₃ = 0.33 A

Learn more about current:

brainly.com/question/25537936

#SPJ4

7 0
1 year ago
The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou
Inessa05 [86]

Answer:

a) 4.40 s

b) 2.20 s

Explanation:

Given parameters are:

At constant power  ,

initial speed of the car, v_0=0

final speed of the car, v=32 mph

At full power,

initial speed of the car, v_0=0

final speed of the car, v=64 mph

a)

At constant power, KE = \frac{1}{2} mv^2

At full power, KE = \frac{1}{2} m(2v)^2

So KE_f = 4KE_i

So, time to reach 64 mph speed is 4 times more than the initial time

t = 4*1.10 =4.40 s

b)

v=v_0+at\\a=\frac{v-v_0}{t}=\frac{32-0}{1.1/3600}=104727.27 miles/hours^2

For final 64 mph speed,

v=v_0+at\\t=\frac{v-v_0}{a}=\frac{64-0}{104727.27} = 6.111*10^{-4} hours = 6.111*10^{-4}*3600=2.20 s

7 0
3 years ago
1. A race car accelerates at a rate of 15.6 m/s. If it starts from rest, how much time till it
musickatia [10]

Answer: 5.79 s

Explanation:

Vs=0 m/s starting speed(from rest)

Vf=325 km/h= 325*1000/3600= 90.28 m/s

a=15.6m/s²

Using equation for acceleration  we can find out time :

a=(Vf-Vs)/t

t=(Vf-Vs)/a

t=(90.28 m/s-0m/s)/15.6 m/s²

t=5.79 s

4 0
3 years ago
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