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Helen [10]
2 years ago
7

Which type of sign helps you identify the location of a crash or breakdown?

Engineering
1 answer:
lawyer [7]2 years ago
8 0

The type of sign helps you identify the location of a crash or breakdown is called a milepost.

  • A milepost sign is sign used to identify the site of crashes or breakdowns.

  • When vehicles breakdown or crash along the road, it is important to put a sign around the place so as to inform other vehicles coming to the part of the about the breakdown. This is done in order to avoid accident.

  • A stop sign is a sign by the side of the road instructing vehicles to stop.

  • Route sign is used to direct or divert to a particular part of the road.

Therefore,

The type of sign helps you identify the location of a crash or breakdown is called a milepost.

Read more:

brainly.com/question/7388737

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What is the maximum thermal efficiency possible for a power cycle operating between 600P'c and 110°C? a). 47% b). 56% c). 63% d)
Anastasy [175]

Answer:

(b) 56%

Explanation:

the maximum thermal efficiency is possible only when power cycle is reversible in nature and when power cycle is reversible in nature the thermal efficiency depends on the temperature

here we have given T₁ (Higher temperature)= 600+273=873

lower temperature T₂=110+273=383

Efficiency of power cycle is given by =1-\frac{T2}{T1}

=1-\frac{383}{873}

=1-0.43871

=.56

=56%

5 0
3 years ago
Which of the following procedures best applies to assessing the embodied energy of a building?
galina1969 [7]

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5 0
2 years ago
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Dafna11 [192]

Answer:

the 1st one i think

Explanation:

6 0
3 years ago
What is chemical engineering​
viktelen [127]

Answer:

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8 0
4 years ago
During an expansion process, the pressure of a gas changes from 15 to 140 psia according to the relation P = aV + b, where a = 5
Dominik [7]

The work done during the process is 359 btu

<u></u>

<u>Explanation:</u>

Given-

P1 = 15psia

P2 = 140 psia

V1 = 7ft³

a = 5 psia/ft³

b = C

P = aV +b

Work done, W = ?

P1 = aV1 + b

15 = 5 (7) + b

b = -20 psia

P2 = aV2 + b

140 = 5 ( V2) - 20

V2 = 32 ft³

The work done by the process is the area under the curve which is trapezoidal.

Therefore,

Work done, W = area of trapezoid

= (P2 + P1 / 2) (V2 - V1)

= ( 140 + 15 / 2 ) ( 32 - 7)

= 1937.5 psia ft³

= 1937.5/ 5.4039 = 359 btu

Therefore, the work done during the process is 359 btu

5 0
3 years ago
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