A long corridor has a single light bulb and two doors with light switch at each door. design logic circuit for the light; assume
that the light is off when both switches are in the same position.
1 answer:
Answer and Explanation:
Let A denote its switch first after that we will assume B which denotes the next switch and then we will assume C stand for both the bulb. we assume 0 mean turn off while 1 mean turn on, too. The light is off, as both switches are in the same place. This may be illustrated with the below table of truth:
A B C (output)
0 0 0
0 1 1
1 0 1
1 1 0
The logic circuit is shown below
C = A'B + AB'
If the switches are in multiple places the bulb outcome will be on on the other hand if another switches are all in the same place, the result of the bulb will be off. This gate is XOR. The gate is shown in the diagram adjoining below.
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Answer:
16 seconds
Explanation:
Given:
C = 60
L = 4 seconds each = 4*4 =16
In this problem, the first 3 timing stages are given as:
200, 187, and 210 veh/h.
We are to find the estimated effective green time of the fourth timing stage. The formula for the estimated effective green time is:
Let's first find the fourth stage critical lane group ratio , using the formula:
Solving for , we have:
Let's also calculate the volume capacity ratio X,
X = 0.704
For the the estimated effective green time of the fourth timing stage, we have:
Substituting figures in the equation, we now have:
15.78 ≈ 16 seconds
The estimated effective green time of the fourth timing stage is 16 seconds