The modulus of elasticity is 44.4GPa
E<u>xplanation:</u>
Given
original length L1=10cm
New length L2=10.036 cm
Force F=16000N

Stress of the bar σ=Force/Area

Change in length ΔL=L2-L1=10.036-10=0.036 cm
Strain is obtained by dividing the change in length by original length
Strain ε=ΔL/L1
=0.036/10=0.0036
Modulus of elasticity=stress/strain
=σ/ε
Pa

Answer:
Answer to this question is option D i.e. unit price.
Explanation:
The unit price of the item can be understood as the price of a single product or one single commodity which forms a part of a group of items. When only one unit is to be sold then here comes the importance of 'unit price.' This is generally helpful in the retail sector where the products are bought in bulk after calculating the per-unit price of each commodity in that particular bulk.
The pressure drop of air in the bed is 14.5 kPa.
<u>Explanation:</u>
To calculate Re:

From the tables air property

Ideal gas law is used to calculate the density:
ρ = 
ρ = 1.97 Kg / 
ρ = 
R =
= 8.2 ×
/ 28.97×
R = 2.83 ×
atm / K Kg
q is expressed in the unit m/s
q = 1.24 m/s
Re =
Re = 2278
The Ergun equation is used when Re > 10,


= 4089.748 Pa/m
ΔP = 4089.748 × 3.66
ΔP = 14.5 kPa
Answer:
The availability of system will be 0.9
Explanation:
We have given mean time of failure = 900 hours
Mean time [to repair = 100 hour
We have to find availability of system
Availability of system is given by 
So availability of system 
So the availability of system will be 0.9