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JulijaS [17]
2 years ago
11

Problem 2

Engineering
1 answer:
mamaluj [8]2 years ago
8 0

Answer:

susmtqjqmjttqmjtqmjtmqutq

Explanation:

bakaf

fjgjgi5j6leny4mjtqjmu5tjmmwtjmjtj

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vovangra [49]

Answer:

how are supposed to help when you can't do anything?

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3 years ago
Read 2 more answers
What engine does the Lexus is300 have?
Nikitich [7]

Answer:

2jz - ge

Explanation:

it has the non turbo 2jz. its the engine the supra has

6 0
3 years ago
One kilogram of air, initially at 5 bar, 350 K, and 3 kg of carbon dioxide (CO2), initially at 2 bar, 450 K, are confined to opp
pentagon [3]

Answer:

Check the explanation

Explanation:

Energy alance of 2 closed systems: Heat from CO2 equals the heat that is added to air in

m_{a} c_{v,a}(T_{eq} -T_{a,i)} =m_{co2} c_{v,co2} (T_{co2,i} -T_{eq)}

1x0.723x(T_{eq} -350)=3x0.780x(450-T_{eq} ) ⇒T_{eq} = 426.4 °K

The initail volumes of the gases can be determined by the ideal gas equation of state,

V_{a,i}  = \frac{mRT_{a,i} }{P_{a,i} }=  \frac{1x (8.314 28.97 kJ kg • °K)x 350°K}{5 bar x 100KPa bar} = 0.201m^{3}

The equilibrium pressure of the gases can also be obtained by the ideal gas equation

P_{eq=\frac{(m_{a}R_{a}T_{eq})+(m_{a}R_{a}T_{eq} ) }{(V_{a,eq}+V_{CO2,eq)} } =\frac{(m_{a}R_{a}T_{eq})+(m_{a}R_{a}T_{eq} ) }{(V_{a,i}+V_{CO2,i)} }

P_{eq}= 1x(8.314 28.97)x426.4+3x(8.314 44)x426.4

                             (0.201+1.275)

= 246.67 KPa = 2.47 bar

6 0
3 years ago
2 Air enters the compressor of a cold air-standard Brayton cycle at 100 kPa, 300 K, with a mass flow rate of 6 kg/s. The compres
lutik1710 [3]
You can see and download from the link

https://tlgur.com/d/GYYVL5lG

Please don't forget to put heart ♥️
5 0
2 years ago
What are the Basic requirements of drinking Water ?
iragen [17]

Answer:

1) free of contaminants, 2) alkaline, and 3) micro-clustered

Explanation:

Hope it helps you

4 0
2 years ago
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