Answer:
nitrogen
Explanation:
because I also had this in exam and I was correct
gold has a natural state of solid however it can be melted into a liquid
Out of the given options, weight is influenced by mass and gravity
Answer: Option A
<u>Explanation:
</u>
The object's mass is defined as the quantity of a matter with which the object is formed. It can change its state of matter but the quantity will remain the same. However, the weight is defined as how much force gravity exerts on the object's mass to pull it.
The mass is always same irrespective the location but the weight may vary from one place to the other while talking for the bigger picture. For example, the object's weight may be 60 kg on Earth but when it is measured on the moon, it will be lesser.
The weight of an object generally has nothing doing with the volume and it doesn't depend solely on the gravitational pull. The mass plays a crucial role.
![W=F=m \times g](https://tex.z-dn.net/?f=W%3DF%3Dm%20%5Ctimes%20g)
Answer:
F'=708.53 N
Explanation:
We have,
The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. It means tat,
![F=kAv^2](https://tex.z-dn.net/?f=F%3DkAv%5E2)
k is constant
If, A = 190 Ft², v = 220 mph, F = 950 pounds
Let's find k first from above data. So,
![k=\dfrac{F}{Av^2}\\\\k=\dfrac{950}{190\times 220^2}\\\\k=0.0001033](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7BF%7D%7BAv%5E2%7D%5C%5C%5C%5Ck%3D%5Cdfrac%7B950%7D%7B190%5Ctimes%20220%5E2%7D%5C%5C%5C%5Ck%3D0.0001033)
It is required to find the lifting force on the wing if the plane slows down to 190 miles per hour. Let F' is the new force. So,
![F'=0.0001033\times 190\times (190)^2\\\\F'=708.53\ \text{pounds}](https://tex.z-dn.net/?f=F%27%3D0.0001033%5Ctimes%20190%5Ctimes%20%28190%29%5E2%5C%5C%5C%5CF%27%3D708.53%5C%20%5Ctext%7Bpounds%7D)
So, the lifting force is 708.53 pounds if the plane slows down to 190 miles per hour.
Suppose that a horizontal force F is applied to a block resting on a rough surface (see Figure 6.1). As long as the applied force F is less than a certain maximum force (Fmax), the block will not move. This means that the net force on the block in the horizontal direction is zero. Therefore, besides the applied force F, there must be a second force f acting on the block. The force f must have a strength equal to F, and it must be pointing in the opposite direction. This force f is called the friction force, and because the block does not move, we are dealing with static friction. Experiments have shown that the force of static friction is largely independent of the area of contact and proportional to the normal force N acting between the block and the surface. The static friction force is
f <= us N