why do we not notice a difference in the fall and winter in the amount of oxygen in the air even when leaves fall off

Explain why greenhouse gases in the atmosphere cause an increase in temperature?

harkovskaia [24]

Any gas in the atmosphere that absorbs and emits thermal infrared radiation is referred to as a greenhouse gas (GHG). These are the primary causes of the greenhouse effect, which causes the Earth's temperature to rise. Earth is warmer because less heat radiates into space.

6 0

2 years ago

What changes dead plants and animals into ammonia compounds?

lapo4ka [179]

Nitrogen fixing bacteria changes dead plants and animals into ammonia compounds.

<h2>What is nitrogen fixation?</h2>

Atmospheric nitrogen is converted into nitrogen oxides by the action of lightning, which helps its incorporation into the soil.

<h3>Characteristics of Nitrogen fixing bacteria</h3>

Nitrogen is fixed by these bacteria and other prokaryotes through various metabolic processes, which convert it into different usable compounds, such as ammonia (NH3) and ammonium ion (NH4+).

These microorganisms can be found in soil and water, or as plant symbionts.

Therefore, we can conclude that nitrogen fixing bacteria fix nitrogen from the air, that is, they originate soluble compounds by plants, such as ammonia.

Learn more about nitrogen fixation here: brainly.com/question/14726009

7 0

1 year ago

A string along which waves can travel is 4.36 m long and has a mass of 222 g. The tension in the string is 60.0 N. What must be

lora16 [44]

Answer:

frequency is 195.467 Hz

Explanation:

given data

length L = 4.36 m

mass m = 222 g = 0.222 kg

tension T = 60 N

amplitude A = 6.43 mm = 6.43 × $10^{-3}$ m

power P = 54 W

to find out

frequency f

solution

first we find here density of string that is

density ( μ )= m/L ................1

μ = 0.222 / 4.36

density μ is 0.050 kg/m

and speed of travelling wave

speed v = √(T/μ) ...............2

speed v = √(60/0.050)

speed v = 34.64 m/s

and we find wavelength by power that is

power = μ×A²×ω²×v / 2 ....................3

here ω is wavelength put value

54 = ( 0.050 ×(6.43 × $10^{-3}$ )²×ω²× 34.64 ) / 2

0.050 ×(6.43 × $10^{-3}$ )²×ω²× 34.64 = 108

ω² = 108 / 7.160 × $10^{-5}$

ω = 1228.16 rad/s

so frequency will be

frequency = ω / 2π

frequency = 1228.16 / 2π

frequency is 195.467 Hz

7 0

3 years ago

How many molecules of Oxygen gas are there on the reactant side of this equation?

Sergeeva-Olga [200]

Answer:

4

Explanation:

It has 8 O atoms and 4 O2(g) molecules

8 0

2 years ago

A glider with mass m = 0.230 kg sits on a frictionless horizontal air track, connected to a spring with force constant k = 4.50

loris [4]

Answer

given,

mass of glider = 0.23 Kg

spring constant = k = 4.50 N/m

spring stretched to 0.130 m

The springs potential energy =

$U = \dfrac{1}{2}kx^2$

$U = \dfrac{1}{2}\times 4.5 \times 0.13^2$

U = 0.038 J

at x = 0,the only energy will be kinetic .

$\dfrac{1}{2}mv^2=0.038$

$\dfrac{1}{2}\times 0.23 \times v^2=0.038$

v² = 0.3304

v = 0.575 m/s

displacement of the glider

using conservation of energy

$\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2$

$x =v\sqrt{\dfrac{m}{k}}$

$x =3\times \sqrt{\dfrac{0.23}{4.5}}$

x = 0.678 m

8 0

2 years ago