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Setler79 [48]
2 years ago
9

What will happen to the period of a ball-on-a-spring if the ball is replaced by a smaller one with half the mass

Physics
1 answer:
Murrr4er [49]2 years ago
4 0

When the ball on a spring is replaced by a smaller ball with half the mass :  The period decrease by 29%

<h3>Calculate the Period </h3>

We will apply the formula below to calculate period

T = 2\pi \sqrt{\frac{m}{k } }

 where :

T₁ / T₂ = \sqrt{\frac{m_{1} }{m_{2} } }    where m₂ = m₁ / 2

Therefore :

T₂ = \frac{T_{1} }{\sqrt{2} }   = 0.71 T

Hence we can conclude that the period will decrease by 29% ( i.e 100 - 71 ).

Learn more about Period calculation : brainly.com/question/10728818

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I just... I don't know man I suck at physics :(
lys-0071 [83]

Answer:

Explanation:

The velocity is 340, but the distance is not. Here's how you do this:

You need to find out the velocity of the that sound in that temp which has a formula of

v = 331.5 + .606T where T is the temp in Celcius. Filling in and using the correct number of sig dig:

v = 331.5 + .606(20) and

v = 331.5 + 10 and

v = 340 m/s. Now we need to use that in d = vt:

d = 340(2.00) so

d = 680 m

3 0
3 years ago
Read 2 more answers
An air bubble underwater has the same pressure as that of the surrounding water. As the air bubble rises toward the surface (and
goldenfox [79]

Answer:

D Remains constant

Explanation:

3 0
3 years ago
Show that linear S.H.M is projection of a U.C.M along any of its diameter
BigorU [14]

It shows that acceleration of particle M is directly proportional to its displacement and its direction is opposite to that of displament. Thus particle M performs simple harmonic motion but M is projection of particle performing U.C.M. hence S.H.M. is projection of U.C.M. along a diameter, of circle.

4 0
3 years ago
The electric field in a region of space has the components Ey = Ez = 0 and Ex = (4.00 N/C · m) x. Point A is on the y axis at y
igor_vitrenko [27]

Answer:

   V_{b}-V_{a} = -38.72

Explanation:

Consider the axis diagram attached.

Given:

                                        Ey = Ez = 0

                                       Eₓ = - 4x N/C · m

Since electric field is in x direction, potential difference would be:

              V_{b} - V_{a} =-\int\limits^{4.40}_{0} {E_{x} } \, dx

Here we integrate between limits 0 and 4.40 which is distance between A and B along x-axis.  

              V_{b} - V_{a} = -4 \left[\begin{array}{ccc}\frac{x^{2} }{2} \end{array}\right]^{4.40}_{0}

                       V_{b}-V_{a} = -4 (9.68)\\V_{b}-V_{a} = -38.72

5 0
3 years ago
14. A block rests on a frictionless table on Earth. After a 20-N horizontal force is applied to the block, it accelerates at 3.9
joja [24]
<span>14. Let's find mass. We know that F = m*a, so m = F/a.m = 20/3,9 m/s^2 = 5,12 kg;We already know the mass, so acceleration will be a = F/m;a = 10/5,12 = 2,0 m/s^2 (approximately);Answer: E.
15. According to the picture given above, let's define all components:These are refer to y: 985N sin(31)= 507;788N cos(32)= 668;411N sin(53)=-328;
And these are refer to x: 985N cos(31)= 844 788N sin(32)= -417 411N cos(53)= -247
And finally let's calculate tan:  tan^-1 (507/844)= 30,98; tan^-1 (668/-417)= -58,02; tan^-1 (-328/-247)= 53,01
According to these calculations we've got: Sum Fx = 179,4 and Sum Fy = 847. Then let's count magnitude:Fsum = rad 179^2 + 847^2 = 865
Then we've got [tex]cos^-1 (179/865) = 77.7 (approximately).
So the most approximate answer is C. 866 N at 78.1° counterclockwise to the x-axis.
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So the answer is B. 1.6 × 10^4 N
20. If my memory serves me well, magnetism is the force that can act through empty space. It's one aspect of the combined electromagnetic force. So the answer is A.
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7 0
3 years ago
Read 2 more answers
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