Answer:
23.8 m
Explanation:
The distance travelled by the zebra can be calculated by using the equation:

where
u is the initial velocity
t is the time
a is the acceleration
For this zebra,
u = 0 since it starts from rest
is the acceleration
Substituting t = 5 s, we find the distance travelled by the zebra:

Answer:
Explanation:the time taken to stop is 7seconds
The distance traveled by the car as it breaks is 63m
Answer:
1.28 m, 14 m/s
Explanation:
At the maximum height, the velocity is 0.
Given:
a = -9.8 m/s²
v₀ = 5.00 m/s
v = 0 m/s
x₀ = 0 m
Find:
x
v² = v₀² + 2a(x - x₀)
(0 m/s)² = (5.00 m/s)² + 2(-9.8 m/s²) (x - 0 m)
x = 1.28 m
The maximum speed is at the bottom of the well.
Given:
a = -9.8 m/s²
v₀ = 5.00 m/s
x₀ = 0 m
x = -8.5 m
Find:
v
v² = v₀² + 2a(x - x₀)
v² = (5.00 m/s)² + 2(-9.8 m/s²) (-8.5 m - 0 m)
v = -13.8 m/s
Rounded to 2 sig-figs, the maximum speed is 14 m/s.