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love history [14]
3 years ago
15

Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th

seconds​
Physics
1 answer:
krek1111 [17]3 years ago
7 0

Answer:

90

Explanation:

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If the earth were twice the distance from the sun that it is now, the gravitational force exerted on it by the sun would be: a)
devlian [24]

Answer:

a) 1/4 what it is now

Explanation:

As we know that force of gravitation between two planets at some distance "r" from each other is given as

F_g = \frac{Gm_1m_2}{r^2}

now since we know that if the distance between Earth and Sun is changed

So the force of gravity will be given as

\frac{F_g'}{F_g} = \frac{r_1^2}{r_2^2}

now we know that the distance between sun and earth is changed to twice the initial distance between them

so we have

r_2 = 2r_1

so new gravitational force between sun and earth is given as

F_g' = \frac{r_1^2}{(2r_1)^2}F_g

F_g' = \frac{1}{4}F_g

4 0
4 years ago
What is one of the drawbacks to the use of solar energy for generating electricity?
-Dominant- [34]
Solar energy is one of the renewable energy sources that is invested around the world because of its large potential. the sun as a free source can sometimes bring a drawback. one of the drawbacks is that it cannot be harnessed when storms or rains are present in the weather. it is also expensive and young.
7 0
3 years ago
A sled plus passenger with total mass m = 52.3 kg is pulled a distance d = 21.8 m across a horizontal, snow-packed surface for w
Vikki [24]

Answer:

Explanation:

Since the sled plus passenger moves with constant velocity , force applied will be equal to frictional force. Let the force applied be F

a ) Frictional force = μ R = F cosφ

R = mg - F sinφ

μ(mg - F sinφ)  = F cosφ

μmg = F (μsinφ+cosφ)

F = μmg / (μsinφ+cosφ)

Work done

= F cosφ x d

= μmg x cosφ x d / (μsinφ+cosφ)

b )Work done

= 0.13 x 52.3 x 9.8 cos36.7 x 21.8 / ( 0.13 sin36.7 +cos36.7)

= 1164.61 / .87946

1324.23 J

c ) work done on the sled by friction

= - (work done by force)

= - μmg x cosφ x d / (μsinφ+cosφ)

d ) work done on the sled by friction

= - 1324.23 J

3 0
4 years ago
a quickly moving house cat has 10 j of kinetic energy at speed v. at what speed will the cat have 20 j of kinetic energy
Brums [2.3K]

Answer:

2.00v

Explanation:

3 0
3 years ago
A soccer player attempting to steal the ball from an opponent was extending her knee at 50 deg/s when her foot struck the oppone
denpristay [2]

Answer:

\alpha = -4.36 rad/s^2

Explanation:

Initial angular speed of the player is given as

\omega = 50 deg/s

here we know that

1 deg = \frac{\pi}{180} rad

now we know that

\omega = 50\frac{\pi}{180}

\omega = 0.87 rad/s

now its speed comes to zero in 0.2 s

so angular acceleration is given as

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

\alpha = \frac{0 - 0.87 rad/s}{0.2 s}

\alpha = -4.36 rad/s^2

7 0
4 years ago
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