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2 years ago

How many grams of H2O2 are in 3 moles of H2O2?

Chemistry

1 answer:

stira [4]2 years ago

4 0

Answer:

The answer is 102.3!

Explanation:

you get this by multiplying 34.1 x 3 to get 102.3.

Wondering why you multiply 34.1 times 3?

WELLLLLLLLLLL...

when you get 1 mole of h202, you get 34.1 so if you ask for 3 moles of H202, you get 102.3!

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Explain how melting is considered endothermic

Eddi Din [679]

Melting is a process involving absorption of energy which means that it is endothermic.

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2 years ago

[CM.01] Which states of matter appear only in the hydrosphere?

vodomira [7]

I will say liquid because the rest all consist of solids and atmosphere also contain gas, but only hydrosphere has liquid.

3 0

3 years ago

Read 2 more answers

Read the summary below. Choose the answer that BEST fits into the blank to complete the summary.

777dan777 [17]

Answer:

An atom has a nucleus, made up protons and neutrons, which is surrounded by a cloud of electrons.

Explanation:

An atom is the smallest indivisible part of any element that takes place in a chemical reactions.

These are the fundamental building blocks of every element and even compounds.

There are three known subatomic particles found within an atom.
Electrons are the negatively charged particles in an atom
Protons are the positively charged particles of an atom
Neutrons do not carry any charges.

Both protons and neutrons are located within the tiny space called nucleus at the center of an atom.

Electrons moves round in orbitals at the spaces outside of the nucleus.

4 0

2 years ago

2Ni(OH) → Ni2O + H2O <br> How many moles of water forms from 4.20 mol of nickel (I) hydroxide?

butalik [34]

Answer:

2.1 moles of water formed.

Explanation:

Given data:

Moles of water formed = ?

Moles of Ni(OH) = 4.20 mol

Solution:

Chemical equation:

2Ni(OH) → Ni₂O + H₂O

Now we will compare the moles of Ni(OH) with water.

Ni(OH) : H₂O

2 : 1

4.20 : 1/2×4.20 = 2.1 mol

2.1 moles of water formed.

5 0

2 years ago

Ammonia, NH3NH3 , can react with oxygen to form nitrogen gas and water. 4NH3(aq)+3O2(g)⟶2N2(g)+6H2O(l) 4NH3(aq)+3O2(g)⟶2N2(g)+6H

solmaris [256]

Answer:

36.37% is the percent yield of the reaction.

Explanation:

$4NH_3(aq)+3O_2(g)\rightarrow 2N_2(g)+6H_2O(l)$

1)0.650 L nitrogen gas , at 295 K and 1.01 bar.

Let the moles of nitrogen gas be n.

Pressure of the gas ,P= 1.01 bar = 0.9967 atm (1 bar = 0.9869 atm)

Temperature of the gas = T = 295 K

Volume of the gas = V = 0.650 L

Using an ideal gas equation:

$PV=nRT$

$n=\frac{PV}{RT}=\frac{0.9967 atm\times 0.650 L}{0.0821 atm L/mol K\times 295 K}=0.0267 mol$

2) Moles of ammonia gas= $\frac{2.53 g}{17 g/mol}=0.1488 mol$

Moles of oxygen gas = $\frac{3.53 g}{32 g/mol}=0.1101 mol$

According to reaction ,3 mol of oxygen reacts with 4 mol of ammonia.

Then,0.1101 mol of oxygen will react with:

$\frac{4}{3}\times 0.1101 mol=0.1468 mol$ of ammonia.

Hence, oxygen gas is in limiting amount and act as limiting reagent.

3) Theoretical yield of nitrogen gas :

According to reaction, 3 mol of oxygen gas gives 2 moles of nitrogen gas.

Then 0.1101 mol of oxygen will give:

$\frac{2}{3}\times 0.1101 mol=0.0734 mol$ of nitrogen.

Theoretical yield of nitrogen gas = 0.0734 mol

Experimental yield of nitrogen as calculated in part (1) = 0.0267 mol

Percentage yield:

$\frac{\text{Experiential yield}}{\text{Theoretical yield}}\times 100$

Percentage yield of the reaction:

$\frac{ 0.0267 mol}{0.0734 mol}\times 100=36.37\%$

36.37% is the percent yield of the reaction.

3 0

3 years ago