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4 years ago

8

The cross-section of a pipe has an area of 2.0 cm2. Calculate the flow rate (in grams per second) of a liquid with p=1.0 g/cm3 t

hrough the pipe if the flow speed is 42 cm/s.
a. 46 g/s
c. 80 g/s
b. 76 g/s
d. 84 g/s

1 answer:

Maurinko [17]4 years ago

4 0

<span> flow rate = velocity of fluid x area of cross section x density
= 42 x 2 x 1 = 84 g/s</span>

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3 years ago

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3 years ago

Read 2 more answers

The membrane that surrounds a certain type of living cell has a surface area of 5.1 x 10-9 m2 and a thickness of 1.4 x 10-8 m.

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a) The charge on the outer surface is $1.2\cdot 10^{-12} C$

b) The number of ions is $7.5\cdot 10^6$

Explanation:

a)

The membrane behaves as a parallel plate capacitor, whose capacity is given by the equation

$C=\frac{k\epsilon_0 A}{d}$

where

k = 4.3 is the dielectric constant

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Substituting,

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The capacity of the membrane is related to the potential difference between the two surfaces by

$C=\frac{Q}{\Delta V}$

where here we have

Q = excess charge on one surface

$\Delta V = 85.5 mV = 0.0855 V$ is the potential difference between the two surfaces

Solving for Q, we find

$Q=C\Delta V=(1.4\cdot 10^{-11})(0.0855)=1.2\cdot 10^{-12} C$

b)

We said that the net charge on the outer surface is

$Q=1.2\cdot 10^{-12} C$

The charge of one K+ ions is equal to the electron charge

$+e=1.6\cdot 10^{-19} C$

Therefore, the number of ions on the outer surface can be found by dividing the total charge by the charge of a single ion:

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