Gravity ALWAYS does that, and electrostatic force does it when two objects have opposite charges.
Answer:
![\frac{g_{2}}{g_{1}} = \frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7Bg_%7B2%7D%7D%7Bg_%7B1%7D%7D%20%3D%20%5Cfrac%7B1%7D%7B4%7D)
Explanation:
The period of the simple pendulum is:
![T = 2\pi\cdot \sqrt{\frac{l}{g} }](https://tex.z-dn.net/?f=T%20%3D%202%5Cpi%5Ccdot%20%5Csqrt%7B%5Cfrac%7Bl%7D%7Bg%7D%20%7D)
Where:
- Cord length, in m.
- Gravity constant, in
.
Given that the same pendulum is test on each planet, the following relation is formed:
![T_{1}^{2}\cdot g_{1} = T_{2}^{2}\cdot g_{2}](https://tex.z-dn.net/?f=T_%7B1%7D%5E%7B2%7D%5Ccdot%20g_%7B1%7D%20%3D%20T_%7B2%7D%5E%7B2%7D%5Ccdot%20g_%7B2%7D)
The ratio of the gravitational constant on planet CornTeen to the gravitational constant on planet Earth is:
![\frac{g_{2}}{g_{1}} = \left(\frac{T_{1}}{T_{2}} \right)^{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bg_%7B2%7D%7D%7Bg_%7B1%7D%7D%20%3D%20%5Cleft%28%5Cfrac%7BT_%7B1%7D%7D%7BT_%7B2%7D%7D%20%5Cright%29%5E%7B2%7D)
![\frac{g_{2}}{g_{1}} = \left(\frac{2\,s}{4\,s} \right)^{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bg_%7B2%7D%7D%7Bg_%7B1%7D%7D%20%3D%20%5Cleft%28%5Cfrac%7B2%5C%2Cs%7D%7B4%5C%2Cs%7D%20%5Cright%29%5E%7B2%7D)
![\frac{g_{2}}{g_{1}} = \frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7Bg_%7B2%7D%7D%7Bg_%7B1%7D%7D%20%3D%20%5Cfrac%7B1%7D%7B4%7D)
Thank you for posting your question here. The total distance traveled by the truck during the 3.2 seconds interval is 83 m. Below is the solution:
d = vit + 1/2 at^2
d = (22m/ s) (3.2s) + 1/2 (2.4m/ s^2) (3.2s)^2
d = 83 m
Hope the answer helps.
Answer:
Mass will not change based on location, while weight will change based on gravitational pull.
Explanation:
The formula for weight is mass*gravitational pull, hence weight changes based on gravitational pull