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Daniel [21]
3 years ago
12

The process of converting a liquid to a gas is known as _____.

Physics
2 answers:
Sloan [31]3 years ago
8 0

This is called vaporization.




hope this helps :)

Ivan3 years ago
8 0
It is called evaporation or vaporization
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padilas [110]
Preserved fossil<span> (like a fossil in amber, ice or tar.</span>
8 0
3 years ago
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8. The mediator particle for gravitational force is on
vodka [1.7K]

Answer:

Gravitone

Explanation:

In theories of quantum gravity, the graviton is the hypothetical quantum of gravity, an elementary particle that mediates the force of gravity. There is no complete quantum field theory of gravitons due to an outstanding mathematical problem with renormalization in general relativity.

6 0
3 years ago
mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan
Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, v_e, for the planet is v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }

Where;

v_e = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, M_E

r = The radius of the planet = 3 × The radius of Earth, R_E

The escape velocity for Earth, v_e_E, is therefore given as follows;

v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }

\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } =  \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E

v_e = 16 × v_e_E

Given that the escape velocity for Earth, v_e_E ≈ 11,186 m/s, we have;

The escape velocity on the planet = v_e ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0
3 years ago
Water runs out of a horizontal drainpipe at the rate of 135 kg/min. It falls 3.1 m to the ground. Assuming the water doesn't spl
Arlecino [84]

Answer:

The average force exerted by the water on the ground is 17.53 N.

Explanation:

Given;

mass flow rate of the water, m' = 135 kg/min

height of fall of the water, h = 3.1 m

the time taken for the water to fall to the ground;

h = ut + \frac{1}{2}gt^2\\\\h = 0 +  \frac{1}{2}gt^2\\\\t = \sqrt{\frac{2\times 3.1}{9.8} } \\\\t = 0.795 \ s

mass of the water;

m = m't\\\\m = 135 \ \frac{kg}{min} \ \times \ 0.795 \ s \ \times \ \frac{1 \ \min}{60 \ s} \ = 1.789 \ kg

the average force exerted by the water on the ground;

F = mg

F = 1.789 x 9.8

F = 17.53 N

Therefore, the average force exerted by the water on the ground is 17.53 N.

7 0
3 years ago
a freight train travels at v=60(1-e^-t) ft/s, where t is the elapsed time in seconds. Determine the distance traeled in tree sec
lesantik [10]

Answer

given,

v = 60(1-e^{-t})\ ft/s

t = 3 s

we know,

v = \dfrac{dx}{dt}

a = \dfrac{dv}{dt}

position of the particle

dx = v dt

integrating both side

\int dx =\int 60(1-e^{-t}) dt

x = 60 t + 60 e^{-t}

Position of the particle at t= 3 s

x = 60\times 3+ 60 e^{-3}

 x = 182.98 ft

Distance traveled by the particle in 3 s is equal to 182.98 ft

now, particle’s acceleration

a = \dfrac{dv}{dt}

a = \dfrac{d}{dt}60(1-e^{-t})

  a = 60 e^{-t}

at t= 3 s

  a = 60 e^{-3}

    a = 2.98 ft/s²

acceleration of the particle is equal to 2.98 ft/s²

7 0
3 years ago
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