you calculate all the letters together and it would be Zn2
Answer:
A. for K>>1 you can say that the reaction is nearly irreversible so the forward direction is favored. (Products formation)
B. When the temperature rises the equilibrium is going to change but to know how is going to change you have to take into account the kind of reaction. For endothermic reactions (the reverse reaction is favored) and for exothermic reactions (the forward reaction is favored)
Explanation:
A. The equilibrium constant K is defined as

In any case
aA +Bb equilibrium Cd +dD
where K is:
![K= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}](https://tex.z-dn.net/?f=K%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%5BD%5D%5E%7Bd%7D%7D%7B%5BA%5D%5E%7Ba%7D%5BB%5D%5E%7Bb%7D%7D)
[] is molar concentration.
If K>>> 1 it means that the molar concentration of products is a lot bigger that the molar concentration of reagents, so the forward reaction is favored.
B. The relation between K and temperature is given by the Van't Hoff equation

Where: H is reaction enthalpy, R is the gas constant and T temperature.
Clearing the equation for
we get:

Here we can study two cases: when delta
is positive (exothermic reactions) and when is negative (endothermic reactions)
For exothermic reactions when we increase the temperature the denominator in the equation would have a negative exponent so
is greater that
and the forward reaction is favored.
When we have an endothermic reaction we will have a positive exponent so
will be less than
the forward reactions is not favored.

1. sundering
2. talc
3 luster
C I believe it is and I think that because I got it right
Answer: One carrier interested in taxonomy is a veterinarian
Explanation:
Veterinarians as said, are interested in taxonomy. They are interested with animal organisms of all types with all species of animals. Hope this helps. Let me know if you need anything else.