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Anuta_ua [19.1K]
3 years ago
6

a 32 gram radioactive sample has a half-life of 2 days how much of the original sample remains after 6 days

Chemistry
1 answer:
DiKsa [7]3 years ago
4 0
<span>After 6 days, only 4 grams of the original amount will remain after 6 days. I have attached an image on how to calculate half-life so you can plug your give value into the formula.

</span><span>
To add, </span>half-life means for<span> a substance decaying exponentially, the amount of time it takes for the amount of the substance to diminish by </span>half.

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A material has a density of 8.9 g/cm^3. You have 3 grams of the substance. How much space does it take up? a. 0.3cm3 b. 3.0 cm3
My name is Ann [436]
D = m/ V

8.9 = 3 / V

V = 3 / 8.9

V = 0.3 cm³

Answer A

hope this helps!
6 0
3 years ago
Read 2 more answers
Need help, please. :)
wolverine [178]

A change of one unit on the pH scale represents a change in the concentration of hydrogen ions by a factor of 10, a change in two units represents a change in the concentration of hydrogen ions by a factor of 100. Thus, small changes in pH represent large changes in the concentrations of hydrogen ions.

6 0
3 years ago
How many moles in 2.21 x10E24 atoms of aluminum
lisov135 [29]
<h3>Answer:</h3>

3.67 mol Al

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.21 × 10²⁴ atoms Al

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 2.21 \cdot 10^{24} \ atoms \ Al(\frac{1 \ mol \ Al}{6.022 \cdot 10^{23} \ atoms \ Al})
  2. Divide:                              \displaystyle 3.66988 \ mol \ Al

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.66988 mol Al ≈ 3.67 mol Al

7 0
3 years ago
Crambury glasses made by adding?<br><br> Gold<br> Manganese<br> Cobalt <br> Chromium
Nataliya [291]

Answer:

Gold

Explanation:

Cranberry glass or 'Gold Ruby' glass is a red glass made by adding gold salts or colloidal gold to molten glass. Tin, in the form of stannous chloride, is sometimes added in tiny amounts as a reducing agent.

7 0
3 years ago
10g of a non-volatile and non-dissociating solute is dissolved in 200g of benzene.
ehidna [41]

<u>Answer: </u>The molar mass of solute is 115 g/mol.

<u>Explanation:</u>

Elevation in the boiling point is defined as the difference between the boiling point of the solution and the boiling point of the pure solvent.

The expression for the calculation of elevation in boiling point is:

\text{Boiling point of solution}-\text{boiling point of pure solvent}=i\times K_b\times m

OR

\text{Boiling point of solution}-\text{Boiling point of pure solvent}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}} ......(1)

where,

Boiling point of pure solvent (benzene) = 80.10^oC

Boiling point of solution = 81.20^oC

i = Vant Hoff factor = 1 (for non-electrolytes)

K_b = Boiling point elevation constant = 2.53^oC/m

m_{solute} = Given mass of solute = 10 g

M_{solute} = Molar mass of solute = ? g/mol

w_{solvent} = Mass of solvent = 200 g

Putting values in equation 1, we get:

81.20-80.10=1\times 2.53\times \frac{10\times 1000}{M_{solute}\times 200}\\\\M_{solute}=\frac{1\times 2.53\times 10\times 1000}{1.1\times 200}\\\\M_{solute}=115g/mol

Hence, the molar mass of solute is 115 g/mol.

4 0
3 years ago
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