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nirvana33 [79]
2 years ago
9

An aqueous solution contains the following ions: cl−, ag , pb2 , no−3, and so2−4. More than one precipitate will form. Identify

the precipitates
Chemistry
1 answer:
klasskru [66]2 years ago
8 0

An aqueous solution contains the following ions Cl⁻, Ag⁺, Pb²⁺, NO₃⁻ & SO₄²⁻ and more than one precipitate will form are AgCl, PbCl₂, PbSO₄ & Ag₂SO₄.

<h3>What is precipitate?</h3>

Precipitate is the insoluble compound which is present at the bottom of any chemical reaction in the solid state.

If in an aqueous solution Cl⁻, Ag⁺, Pb²⁺, NO₃⁻ & SO₄²⁻ ions are present then:

  • Compounds AgCl, PbCl₂, PbSO₄ & Ag₂SO₄ are not soluble in water as it is present in the form of precipitate.
  • Pb(NO₃)₂ is fully soluble in water and will not make precipitate.

Hence precipitates are AgCl, PbCl₂, PbSO₄ & Ag₂SO₄.

To know more about precipitates, visit the below link:

brainly.com/question/2437408

#SPJ4

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If you have an aqueous solution that contains 1.5 moles of hcl, how many moles of ions are in the solution? (a) 1.0, (b) 1.5, (c
Darya [45]

If you have an aqueous solution that contains 1.5 moles of HCl, the number of moles of ions in the solution is 3.0 moles.

<h2>Further Explanation </h2><h3>Strong acids  </h3>
  • Strong acids are types of acids that undergo complete dissociation to form ions when dissolved in water.
  • Examples of such acids are, HCl, H2SO4 and HNO3
  • Dissociation of HCl

HCl + H₂O ⇔ H₃O⁺ + OH⁻

<h3>Weak acids  </h3>
  • Weak acids are types of acids that undergo incomplete dissociation to form ions when dissolved in water.
  • Examples of such acids are acetic acids and formic acids.
  • Dissociation of  acetic acid

H₃COOH ⇔ CH₃COO⁻ + H⁺; CH₃COO⁻ is a conjugate base of acetic acid.

<h3>In this case;</h3>
  • HCl which is a strong acid that ionizes completely according to the equation;

HCl + H₂O ⇔ H₃O⁺ + OH⁻

  • From the equation, 1 mole of HCl produces 1 mole of H₃O⁺ ions and 1 mole of OH⁻ ions.

Therefore;

1.5 moles of HCl will produce;

= 1.5 moles of H₃O⁺ ions and 1.5 moles of OH⁻ ions.

This gives a total number ions of;

= 1.5 + 1.5

= 3 moles of ions

Keywords:  Strong acid, weak acid, ions, ionization

<h3>Learn more about: </h3>
  • Strong acid: brainly.com/question/3239966
  • Weak acid; brainly.com/question/3239966
  • Ionization of acids and bases: brainly.com/question/11844503

Level: High school

Subject: Chemistry

Topic: Salts, Acids and Bases

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Give the number of significant figures indicated 78
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2 significant figures

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If an experiment calls for 0.200mole acetic acid (Hc2H3O2)how many grams of glacial acetic acid do we need?
bija089 [108]
<h3>Molar mass:-</h3>

\\ \sf\longmapsto HC_2H_3O_2

\\ \sf\longmapsto 1u+2(12u)+3(1u)+2(16u)

\\ \sf\longmapsto 1u+24u+3u+48u

\\ \sf\longmapsto 28u+48u

\\ \sf\longmapsto 76u

\\ \sf\longmapsto 76g/mol

  • No of moles=0.2mol
  • Given mass=?

\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}

\\ \sf\longmapsto 0.2=\dfrac{Given\:mass}{76}

\\ \sf\longmapsto Given\:Mass=0.2\times 76

\\ \sf\longmapsto Given\:Mass=1.52g

7 0
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What is the distinction between magma and lava​
BabaBlast [244]

Answer:

Scientists use the term magma for molten rock that is underground and lava for molten rock that breaks through the Earth's surface.

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If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produc
hodyreva [135]

Answer: 69.72 kg of cryolite will be produced.

Explanation:

The balanced chemical equation is:

Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of Al_2O_3 = \frac{16.9\times 1000g}{102g/mol}=165.7moles

moles of NaOH = \frac{57.4\times 1000g}{40g/mol}=1435moles

moles of HF = \frac{57.4\times 1000g}{20g/mol}=2870moles

As 1 mole of Al_2O_3 reacts with 6 moles of NaOH

166 moles of  Al_2O_3 reacts with = \frac{6}{1}\times 166=996 moles of NaOH

As 1 mole of Al_2O_3 reacts with 12 moles of HF

166 moles of  Al_2O_3 reacts with = \frac{12}{1}\times 166=1992 moles of HF

Thus Al_2O_3 is the limiting reagent.

As 1 mole of Al_2O_3 produces = 2 moles of cryolite

166 moles of  Al_2O_3 reacts with = \frac{2}{1}\times 166=332 moles of cryolite

Mass of cryolite (Na_3AlF_6) = moles\times {\text {molar mass}}=332mol\times 210g/mol=69720g=69.72kg

Thus 69.72 kg of cryolite will be produced.

8 0
3 years ago
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