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nirvana33 [79]
2 years ago
9

An aqueous solution contains the following ions: cl−, ag , pb2 , no−3, and so2−4. More than one precipitate will form. Identify

the precipitates
Chemistry
1 answer:
klasskru [66]2 years ago
8 0

An aqueous solution contains the following ions Cl⁻, Ag⁺, Pb²⁺, NO₃⁻ & SO₄²⁻ and more than one precipitate will form are AgCl, PbCl₂, PbSO₄ & Ag₂SO₄.

<h3>What is precipitate?</h3>

Precipitate is the insoluble compound which is present at the bottom of any chemical reaction in the solid state.

If in an aqueous solution Cl⁻, Ag⁺, Pb²⁺, NO₃⁻ & SO₄²⁻ ions are present then:

  • Compounds AgCl, PbCl₂, PbSO₄ & Ag₂SO₄ are not soluble in water as it is present in the form of precipitate.
  • Pb(NO₃)₂ is fully soluble in water and will not make precipitate.

Hence precipitates are AgCl, PbCl₂, PbSO₄ & Ag₂SO₄.

To know more about precipitates, visit the below link:

brainly.com/question/2437408

#SPJ4

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Which best explains why ionization energy tends to decrease from the top to the bottom of a group? The number of orbitals decrea
cluponka [151]

Answer:

Electrons get farther from the nucleus.

Explanation:

By going from the top to the bottom of a group, the atomic number increases. That would mean that:

  • The number of orbitals increases, as there are more electrons.
  • A higher atomic number implies an increasing number of neutrons.
  • As there are more electrons, they get farther from the nucleus. The farther an electron is from the nucleus, the easier it is for the electron to be removed from the atom.
4 0
3 years ago
Whether or not the process is observed in nature, which of the following could account for the transformation of gallium-67 to z
Sonja [21]

Answer:

Option a: positron emission.

Explanation:

In the transformation we have:

⁶⁷Ga  →  ⁶⁷Zn  

The reaction is:

^{67}_{Z}X \rightarrow ^{67}_{Z -1}Y

For Ga to become Zn, the atom nucleus has to lose a proton, so in the given options, the reaction that involves the transformation of a proton is the option a, positron emission.

In a positron emission, a proton becomes into a neutron and a positron:

^{A}_{Z}X \rightarrow ^{A}_{Z-1}Y + ^{0}_{+1}e

Therefore, the correct answer is option a: positron emission.

I hope it helps you!

7 0
2 years ago
A sheet of gold weighing 8.8 g and at a temperature of 10.5°C is placed flat on a sheet of iron weighing 19.5 g and at a tempera
timofeeve [1]

Answer:

T = 36.393\,^{\textdegree}C

Explanation:

The contact between the sheet of gold and the sheet of iron allows a heat transfer until thermal equilibrium is done, which means that both sheets have the same temperature:

-Q_{iron} = Q_{gold}

-(0.008\,kg)\cdot (452\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-54.4\,^{\textdegree}C) = (0.0195\,kg)\cdot (129\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-10.5\,^{\textdegree}C)

-(3.616\,\frac{J}{^{\textdegree}C})\cdot (T-54.4\,^{\textdegree}C) = (2.515\,\frac{J}{^{\textdegree}C})\cdot (T-10.5^{\textdegree}C)

-1.438\cdot (T - 54.4^{\textdegree}C) = T-10.5^{\textdegree}C

-1.438\cdot T +78.227^{\textdegree}C = T - 10.5^{\textdegree}C

2.438\cdot T = 88.727\,^{\textdegree}C

The final temperature is:

T = 36.393\,^{\textdegree}C

8 0
3 years ago
Read 2 more answers
Identify the examples of diffusion in the list below
Sergeu [11.5K]

Answer:

movement of particles of object from one place to another

e.g

spreading of perfume in air

spreading of ink in water

Explanation:

3 0
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A patient receives 3.3 L of glucose solution intravenously (IV). If 100. mL of the solution
artcher [175]

Answer:

660kcal

Explanation:

The question is missing the concentration of the glucose solution. Standard glucose concentration for IV solution is 5% or 5g of glucose every 100mL of solution.  

We need to determine how many grams of glucose are there inside the solution. The number of glucose in 3.3L solution will be:  

3.3L * (1000mL / L) * (5g/100mL)= 165 g.

If glucose will give 4kcal/ g, then the total calories 165g glucose give will be: 165g * 4kcal/ g= 660kcal.

6 0
3 years ago
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