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Finger [1]
3 years ago
11

A system is said to be closed if _____ the system.

Physics
1 answer:
hoa [83]3 years ago
5 0
No net force acts on it.example is the earth
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List 3 examples of how organisms respond to changes in their environment
AnnyKZ [126]
1. They will most likely die.
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3. They will go somewhere else to find, an environment similar to there similar one.
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4 years ago
Is there gravity in space? If so name one piece of evidence
Eddi Din [679]
There is gravity everywhere in space. In fact, it's how the moon orbits the Earth. Also, gravity in space assists the Earth to orbit the sun. These are caused by small areas of gravity. The term for this is called "microgravity".

I hope this helps!
8 0
4 years ago
Two balls of mass m1 and m2, with velocities v1 and v2 collide head on. Is there any way for both balls to have zero velocity af
nordsb [41]

Answer:

Explanation:

As the final Kinetic energy is zero or less than initial kinetic energy, the collision must be inelastic.  

In Inelastic collision both the bodies must stick together as final velocity is zero for both the bodies.

To conserve the momentum, momentum associated before the collision of first must be equal and opposite to the momentum associated with the second ball.

i.e.

m_1v_1=m_2v_2

8 0
4 years ago
A force F = (2.75 N)i + (7.50 N)j + (6.75 N)k acts on a 2.00 kg mobile object that moves from an initial position of d = (2.75 m
Natasha2012 [34]

Answer:

The work done on the object by the force in the 5.60 s interval is 40.93 J.

Explanation:

Given that,

Force F=(2.75\ N)i+(7.50\ N)j+(6.75\ N)k

Mass of object = 2.00 kg

Initial position d=(2.75)i-(2.00)j+(5.00)k

Final position d=-(5.00)i+(4.50)j+(7.00)k

Time = 4.00 sec

We need to calculate the work done on the object by the force in the 5.60 s interval.

Using formula of work done

W=F\cdot d

W=F\cdot(d_{f}-d_{i})

Put the value into the formula

W=(2.75)i+(7.50)j+(6.75)k\cdot (-(5.00)i+(4.50)j+(7.00)k-(2.75)i+(2.00)j-(5.00)k)

W=(2.75)i+(7.50)j+(6.75)k\cdot((-7.75)i+6.50j+2.00k)

W=2.75\times-7.75+7.50\times6.50+6.75\times2.00

W=40.93\ J

Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.

4 0
3 years ago
A freight train rolls along a track with considerable momentum. If it rolls at the same speed but has twice as much mass, its mo
GREYUIT [131]

Answer:

doubled

Explanation:

<u>Step 1</u>. Linear momentum (p) = mass X velocity = mv

p = mv -----equation 1

<u>Step 2</u>. if the mass is now twice and speed is same

p = (2*m)v -----equation 2

solving equation 1 and 2 together,

p = mv = 2mv

p = 2

Therefore, its momentum is doubled

7 0
3 years ago
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