Answer: a) 1.05kW b) 3.78MJ c) 5.3 bars
Explanation :
A)
Conversions give 900 kcal as 900000 x 4.2 J/cal {4.2 J/cal is the standard factor}
= 3780kJ
And 1 hour = 3600s
Therefore, Power in watts = 3780/3600 = 1.05kW = 1050W
B)
At 15km/hour a 15km run takes 1 hour.
1 hour is 3600s and the runner burns 1050 joule per second.
Energy used in 1 hour = 3600 x 1050 J/s
= 3780000 J or 3.78MJ
C)
1 mile = 1.61km so 13.1 mile is 13.1 x 1.61 = 21.1km
15km needs 3.78 MJ of energy therefore 21.1km needs 3.78 x 21.1/15 = 5.32MJ =5320 kJ
Finally,
1 Milky Way = 240000 calories = 4.2 x 240000 J = 1008000J or 1008kJ
This means that the runner needs 5320/1008 = 5.3 bars
Answer:
82.62%
Explanation:
The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
From the normal distribution table, P(11.85 < x < 12.15) = P(-1.36 < z < 1.36) = P(z < 1.36) - P(z < -1.36) = 0.9131-0.0869 = 0.8262 = 82.62%
Answer:
development
forming stage - The team transitions into this stage after completion of its first successful project.
storming stage - In this stage, comfort and trust between the members is high.
norming stage - In this stage, the team members come together for the first time.
performing stage- In this stage, the members have a better idea of what the team expects of them.
Answer:
w = 0.626 rad / s, v = 3.13 m/s
Explanation:
For this exercise let's use Newton's second law
F = m a
Where the force is a friction force and the acceleration is centripetal,
a = v² / r = w² r
The formula for friction force
fr = μ N
In a free body diagram
N- W = 0
W = N
The frictiμon outside goes from zero to the maximum value, let's calculate the speed for the maximum value of the friction force, replace
μ m g = m w² r
w = √ μ g / r
Let's calculate
w = √(0.2 9.8 / 5)
w = 0.626 rad / s
angular and linear velocity are related
v = w r
v = 0.626 5
v = 3.13 m/s
