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labwork [276]
3 years ago
9

You are hired as the investigators to identify the root cause and describe what should have occurred based on the following info

rmation. The mass of jet fuel required to travel from Toronto to Edmonton is 22,300 kg. The fuel gage correctly indicated that the plane already had 7,682 L of jet fuel in the tank. The specific gravity of the jet fuel is 0.803. Using this information, the crew added 4,916 L of fuel and took off, only to run out of fuel and crash a short while later. Use your knowledge of dimensions and units to work out what went wrong.
Engineering
1 answer:
creativ13 [48]3 years ago
4 0

Answer:

The mass of fuel added, which is 10,166.2 kg is less than 22,300 kg which is the mass of fuel required to travel from Toronto to Edmonton, the plane therefore crashed.

Explanation:

Since density ρ = m/v where m = mass of fuel and v = volume of fuel, we need to find the mass of each volume of fuel.

So, m = ρv now ρ = specific gravity × density of water = 0.803 × 1000 kg/m³ = 803 kg/m³.

To find the mass of the 7,682 L of fuel, its volume is 7,682 dm³ = 7,682 dm³ × 1 m³/1000 dm³ = 7.682 m³.

It's mass, m = 803 kg/m³ × 7.682 m³ = 6168.646 kg

To find the mass of the extra 4,916 L of fuel added, we have

m' = ρv' where v' = 4,916 L = 4,916 dm³ = 4916 dm³ × 1 m³/1000 dm³ = 4.916 m³

m' =  803 kg/m³ × 4.916 m³ = 3947.548 kg

So, the total mass of the fuel is m" = m + m' = 6168.646 kg + 3947.548 kg = 10116.194 kg ≅ 10,166.2 kg

<u>Since this mass of fuel added, which is 10,166.2 kg is less than 22,300 kg which is the mass of fuel required to travel from Toronto to Edmonton, the plane therefore crashed.</u>

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Answer:

Total change in energy = 31 KJ.

Explanation:

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E_1=25\times 10\times 1+0

E_1=250\ J

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E_2=0+\dfrac{1}{2}\times 25\times 50^2

E_2=31250\ J

So the change in energy = 31250 -250 J

The total change in energy = 31000 J

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void bubble_sort( int A[ ], int n ) {

     int temp;

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4 years ago
Your family has asked you to estimate the operating costs of your clothes dryer for the year. The clothes dryer in your home has
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Answer:

The costs to run the dryer for one year are $ 9.03.

Explanation:

Given that the clothes dryer in my home has a power rating of 2250 Watts, and to dry one typical load of clothes the dryer will run for approximately 45 minutes, and in Ontario, the cost of electricity is $ 0.11 / kWh, to calculate the costs to run the dryer for one year the following calculation must be performed:

1 watt = 0.001 kilowatt

2250/45 = 50 watts per minute

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8 0
3 years ago
The current drawn by fluorescent lighting has a high total harmonic distortion. For this case, THD is calculated to be 88%. The
Alona [7]

Answer:

displacement power factor is 0.959087

Explanation:

given data

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solution

we get here total harmonic distribution THD is express as here

THD = \sqrt{\frac{1}{g^2}-1}       ..............1

her g is distortion factor

so put here value and we will get g that is

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solve it we get

g = 0.750714

and

displacement power factor is express as

DPF = \frac{PF}{g}   .................2  

put here value and we will get

DPF = \frac{0.72}{0.750714}    

DPF  = 0.959087

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