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sergey [27]
3 years ago
15

Which element is placed in the same period as ruthenium but has a higher atomic number than it? bismuth osmium silver zirconium

Chemistry
2 answers:
Nat2105 [25]3 years ago
3 0

The element that is placed in the same period as ruthenium but which has a higher atomic number than it is SILVER.

In the periodic table, a period refers to an horizontal row of elements. All the element in a particular period always have the same number of atomic orbitals. Ruthenium and silver are in the same period and they have the same number of atomic orbital but have different atomic numbers. The atomic number of silver [47] is higher than that of ruthenium [44] because silver has higher number of protons more than ruthenium. Remember that, the number of proton of an element determines its atomic number and the elements in the periodic table are arranged based on increased atomic number.

SVEN [57.7K]3 years ago
3 0
The answer is silver because its in the same transition metal placement and row as the ruthenium metal
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A strong electrolyte dissociates completely into its ions but in weak electrolyte only certain number of ions are dissociated so pH depends upon the dissociated ions.

Definition of pH

An evaluation of how basic a substance or solution is its pH is determined. pH is measured on a scale from 0 to 14. A pH value of 7 is considered to be neutral on this scale, which implies it is neither acidic nor basic. If the pH value is less than 7, it is considered to be acidic and if the pH value is greater than 7, it is considered to be basic.

pH < 7 for NH₃ and HClO₄ since the acid is strong acid and the base is weak base.

The pH value for NaOH and Benzoic acid is pH > 7, since the base is strong base and acid is a weak acid .

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Learn more about acids and bases from the given link given below.

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1 year ago
What must a food handler use to determine the concentration of sanitizing solution?
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What’s the difference between heterogeneous and homogeneous mixtures?
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You need to make an aqueous solution of 0.207 M calcium acetate for an experiment in lab, using a 300 mL volumetric flask. How m
jeka94

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We have to add 9.82 grams of calcium acetate

Explanation:

Step 1: Data given

Molarity of the calcium acetate solution = 0.207 M

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Step 2: Calculate moles calcium acetate

Moles calcium acetate = molarity * volume

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