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Len [333]
3 years ago
12

The following is a list of weak acids and their Ka values.HOCl hypochlorous acid 3.5 x 10^-8H2S hydrogen sulfide 1.1 x 10^-7HCN

hydrocyanic acid 4.0 x 10^-10HNO2 nitrous acid 4.5 x 10^-4a. Which acid given above is the strongest? Explain your choiceb. Write the Ka expression for the strongest acid.c. List the conjugate bases of each of the weak acids above and determine their Kb values.d. Which acid has the strongest conjugate base? Explain your choice.e. Determine the pH and pOH of a 0.1M solution of each.

Chemistry
1 answer:
notsponge [240]3 years ago
5 0

Answer:

(a) HNO₂ nitrous acid 4.5 x 10^-4 is strong acid

(b) Ka expression Ka = \frac{[H^{+}][NO_{2}  ^{-}] }{[HNO_{2}] }

(c) List of Conjugate Bases

OCl⁻, S²⁻, CN⁻, NO₂⁻

(d) cyanide ion is strongest conjugate base.

(e) pH and pOH of Hypochlorous acid = 4.22 & 9.77

     pH and pOH of hydrogen sulfide = 4 & 10

    pH and pOH of  hydrocyanic acid = 5.2 & 8.79

    pH and pOH of  nitrous acid = 2.17 & 11.8

Explanation:

(a) Ka and acidity are directly proportional to each other

hence nitrous acid is the strongest acid since it has highest Ka value.

(b) Ka expression of nitrous acid  

                              HNO₂ → H⁺ + NO₂⁻

                     ⇒       Ka = \frac{[H^{+}][NO_{2}  ^{-}] }{[HNO_{2}] }

(c) Conjuagte base for HOCl hypochlorous acid = OCl⁻(hypochlorite ion)

                                 H₂S hydrogen sulfide = S²⁻(sulphide ion)

                                 HCN hydrocyanic acid = CN⁻(cyanide ion)

                                 HNO₂ nitrous acid = NO₂⁻(nitrite ion)

<u>(d) We know according to Bronsted acid base  concept Weak acid have strongest conjugate base</u>

according to this hydrocyanic acid is weak acid so the corresponding conjugate base i.e. cyanide ion is strongest conjugate base.

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1. Equilibrium constant might be written using standard guidelines:

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Based on the guidelines, we have two ions on the product side, a solid on the left side. Thus, the equilibrium constant has the following expression:

K_eq = [Ca^{2+][OH^-]^2 = K_{sp}

2. a. In the following problems, we'll be considering the common ion effect. According to the principle of Le Chatelier, an increase in concentration of any of the ions would shift the equilibrium towards the formation of our precipitate.

In this problem, we're adding calcium carbonate. It is insoluble, so it wouldn't have any effect on the equilibrium.

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