The final temperature is 83 K.
<u>Explanation</u>:
For an adiabatic process,
![T {V}^{\gamma - 1} = \text{constant}](https://tex.z-dn.net/?f=T%20%7BV%7D%5E%7B%5Cgamma%20-%201%7D%20%3D%20%5Ctext%7Bconstant%7D)
![\cfrac{{T}_{2}}{{T}_{1}} = {\left( \cfrac{{V}_{1}}{{V}_{2}} \right)}^{\gamma - 1}](https://tex.z-dn.net/?f=%5Ccfrac%7B%7BT%7D_%7B2%7D%7D%7B%7BT%7D_%7B1%7D%7D%20%3D%20%7B%5Cleft%28%20%5Ccfrac%7B%7BV%7D_%7B1%7D%7D%7B%7BV%7D_%7B2%7D%7D%20%5Cright%29%7D%5E%7B%5Cgamma%20-%201%7D)
Given:-
![{T}_{2} = T \left( \text{say} \right)](https://tex.z-dn.net/?f=%7BT%7D_%7B2%7D%20%3D%20T%20%5Cleft%28%20%5Ctext%7Bsay%7D%20%5Cright%29)
![{V}_{1} = V](https://tex.z-dn.net/?f=%7BV%7D_%7B1%7D%20%20%3D%20V)
![{V}_{2} = 6V](https://tex.z-dn.net/?f=%7BV%7D_%7B2%7D%20%3D%206V)
(the gas is monoatomic)
![\therefore \cfrac{T}{275} = {\left( \cfrac{V}{6V} \right)}^{\frac{5}{3} - 1}](https://tex.z-dn.net/?f=%5Ctherefore%20%5Ccfrac%7BT%7D%7B275%7D%20%3D%20%7B%5Cleft%28%20%5Ccfrac%7BV%7D%7B6V%7D%20%5Cright%29%7D%5E%7B%5Cfrac%7B5%7D%7B3%7D%20-%201%7D)
T = 275
0.30
T = 83 K.
Answer:
![a=9.8 rad/s^{2}](https://tex.z-dn.net/?f=a%3D9.8%20rad%2Fs%5E%7B2%7D)
Explanation:
Torque,
is given by
where F is force and r is perpendicular distance
where
is the angle of inclination
Torque,
can also be found by
where I is moment of inertia and a is angular acceleration
Therefore, Fr=Ia and F=mg where m is mass and g is acceleration due to gravity
Making a the subject,
and already I is given as
hence
Taking g as 9.81,
is given as 37 and L is 1.2
Answer:
This can be used to find out the speed of the returned journey. The equation means speed = returned distance ÷ time.
Explanation: