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lesya [120]
1 year ago
14

What are the types of realistic fiction?.

Physics
1 answer:
Daniel [21]1 year ago
8 0

The types of realistic fiction:<u> are </u><u>historical </u><u>and </u><u>contemporary </u><u>fiction.</u>

Practical fiction creates imaginary characters and conditions that depict our world and society. It focuses on themes of growing up and confronting non-public and social problems. This genre portrays characters coming to apprehend themselves and others.

Realistic Fiction is divided into two elements: ancient and modern-day fiction. ancient fiction takes place in a time far-flung enough to be taken into consideration records, as opposed to contemporary fiction which takes vicinity these days or within the recent beyond. sensible fiction is a style of testimonies in which the events are made up, but they may easily occur in actual existence. those styles of stories take place in acquainted, ordinary settings and have normal characters.

Learn more about Realistic Fiction here:

brainly.com/question/14596007

#SPJ4

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Yes you would be doing more work

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3 years ago
Read 2 more answers
What is the ionisation energy of an atom
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Explanation:

its the minimum amount of energy required to remove the most loosely bound electron

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What two gases probably dominated precambrian earth's atmosphere?
galben [10]
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8 0
3 years ago
a car travelling at 50km/h from rest covers a distance of 10km in 40minutes. Calculate the acceleration​
Margarita [4]

Answer:

9.67\cdot 10^{-3}m/s^2

Explanation:

We can solve the problem by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the car in this problem:

u = 0 (it starts from rest)

v=50 km/h \cdot \frac{1000}{3600}=13.9 m/s is the final velocity

s = 10 km = 10 000 m is the displacement

Solving for a, we find:

a=\frac{v^2-u^2}{2s}=\frac{13.9^2}{2(10000)}=9.67\cdot 10^{-3}m/s^2

7 0
3 years ago
3. A 5 gm/100 ml solution of drug X is stored in a closed test tube
JulijaS [17]

Answer:

See explanation

Explanation:

The degradation of the drug is a first order process;

Hence;

ln[A] = ln[A]o - kt

Where;

ln[A] = final concentration of the drug

ln[A]o= initial concentration of the drug = 5 gm/100

k= degradation constant = 0.05 day-1

t= time taken

When [A] =[ A]o - 0.5[A]o = 0.5[A]o

ln2.5 = ln5 - 0.05t

ln2.5- ln5 = - 0.05t

t= ln2.5- ln5/-0.05

t= 0.9162 - 1.6094/-0.05

t= 14 days

b) when [A] = [A]o - 0.9[A]o = 0.1[A]o

ln0.5 = ln5 -0.05t

t= ln0.5 - ln5/0.05

t= -0.693 - 1.6094/-0.05

t= 46 days

5 0
3 years ago
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