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lesya [120]
1 year ago
14

What are the types of realistic fiction?.

Physics
1 answer:
Daniel [21]1 year ago
8 0

The types of realistic fiction:<u> are </u><u>historical </u><u>and </u><u>contemporary </u><u>fiction.</u>

Practical fiction creates imaginary characters and conditions that depict our world and society. It focuses on themes of growing up and confronting non-public and social problems. This genre portrays characters coming to apprehend themselves and others.

Realistic Fiction is divided into two elements: ancient and modern-day fiction. ancient fiction takes place in a time far-flung enough to be taken into consideration records, as opposed to contemporary fiction which takes vicinity these days or within the recent beyond. sensible fiction is a style of testimonies in which the events are made up, but they may easily occur in actual existence. those styles of stories take place in acquainted, ordinary settings and have normal characters.

Learn more about Realistic Fiction here:

brainly.com/question/14596007

#SPJ4

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Which property of light remains unchanged when it enters a different medium?
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3 years ago
A bungee cord is 30m long and when stretched a distance x itexerts a restoring force of magnitude kx. Your father-in-law (mass95
madam [21]

Answer:

The distance the bungee cord that would be stretched 0.602 m, should be selected when pulled by a force of 380 N.

Explanation:

As from the given data

the length of the rope is given as l=30 m

the stretched length is given as l'=41m

the stretched length required is give as  y=l'-l=41-30=11m

the mass is m=95 kg

the  force is  F=380 N

the gravitational acceleration is g=9.8 m/s2

The equation of  k is given by equating the energy at the equilibrium point which is given as

U_{potential}=U_{elastic}\\mgh=\dfrac{1}{2} k y^2\\k=\dfrac{2mgh}{y^2}

Here

m=95 kg, g=9.8 m/s2, h=41 m, y=11 m so

k=\dfrac{2mgh}{y^2}\\k=\dfrac{2\times 95\times 9.8\times 41}{11^2}\\k=630.92 N/m

Now the force is

F=kx\\ or

x=\dfrac{F}{k}\\

So here F=380 N, k=630.92 N/m

x=\dfrac{F}{k}\\x=\dfrac{380}{630.92}\\x=0.602 m

So the distance is 0.602 m

6 0
3 years ago
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