water is flowing at 4.0m/s in a circular path. if the diameter of the decreases to 1/2 its former value, what is the velocity of
1 answer:
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Answer:
1.03m/s
Explanation:
According to the question
Fdrag = bv²
now Fdrag = weight of the box
that is Fdrag = mg
where m = mass of the box, 0.6 Kg
and g = acceleration due to gravity
thus,
Fdrag = bv² becomes
mg = bv²
making v the subject of formula
v = 1.03m/s
Answer:
Given that
For A weight Wt= 22.7 N
m₁ = 22.7/10 = 2.27 kg
Force alone inclined plane
Wt₁ = m₁ g sin θ
Wt₁ =22.7 sin 17.2°
Wt₁ = 6.7 N
For B weight Wt₂= 34.5-N
m₂ = 3.45 kg
coefficient of friction ,μ= 0.219
θ = 17.2 degree
The friction force on the block A
Fr= μ m₁ g cos θ
Fr= 0.216 x 22.7 x cos 17.2°
Fr= 4.68 N
Lets take acceleration of system is a m/s²
Tension = T
From Newtons law
Wt₂ - Wt₁ - Fr = (m₁ +m₂) a
34.5 - 6.7 - 4.68 = (2.27 + 3.45 ) a
a= 4.05 m/s²
Block B
Wt₂ - T = m₂ a
T = 34.5 - 4.05 x 3.45
T= 20.52 N
Answer:
Force = 1544.4N
Explanation:
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
Where;
- a is acceleration measured in
- v and u is final and initial velocity respectively, measured in
- t is time measured in seconds.
<u>Given the following data;</u>
Mass, m = 540kg
Initial velocity, u = 27m/s
Final velocity, v = 31m/s
Time, t = 1.4 secs
<em>To find the acceleration:</em>
Acceleration, a = 2.86m/s²
<em>Now to find the Force;</em>
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
Where;
- F represents force measured in Newton.
- m represents the mass of an object measured in kilograms.
- a represents acceleration measured in meter per seconds square.
<em>Substituting into the equation, we have;</em>
Force = 1544.4N
<em>Therefore, the force given by the booster rocket to the satellite is 1544.4 Newton. </em>