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3 years ago

Rank the items from slowest to faster

Physics

1 answer:

valentinak56 [21]3 years ago

5 0

Answer:since time goes to the right you look at the lines that are most pointed to the right with less distance so that would be B, A, D, C

Explanation:

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A pizza parlor is considering adding taco pizza and Hawaiian pizza to its

tia_tia [17]

Answer: 79

Explanation:

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3 years ago

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A mercury thermometer is constructed as

Tamiku [17]

Answer:

The change in height of the mercury is approximately 2.981 cm

Explanation:

Recall that the formula for thermal expansion in volume is:

$\frac{\Delta V}{V_0} =\alpha_V\, \Delta\, T\\\Delta V = V_0\,\, \alpha_V\,\,\Delta C$

from which we solved for the change in volume $\Delta V$ due to a given change in temperature $\Delta T$

We can estimate the initial volume of the mercury in the spherical bulb of diameter 0.24 cm ( radius R = 0.12 cm) using the formula for the volume of a sphere:

$V_0=\frac{4}{3} \pi \, R^3\\V_0=\frac{4}{3} \pi \, (0.12\,cm)^3\\V_0=0.007238\,cm^3$

Therefore, the change in volume with a change in temperature of 36°C becomes:

$\Delta V = V_0\,\, \alpha_V\,\,\Delta C\\\Delta V = 0.007238229\, cm^3\,(0.000182)\,(36)\\\Delta V=0.0000474248\, cm^3$

Now, we can use this difference in volume, to estimate the height of the cylinder of mercury with diameter 0.0045 cm (radius r= 0.00225 cm):

$V_{cyl}=\pi r^2\,h\\h =\frac{V_{cyl}}{\pi r^2} \\h=\frac{0.0000474248\, cm^3}{\pi \, (0.00225\,cm)^2} \\h=2.98188 \,cm$

8 0

3 years ago

Why are units of measurement useful?

Zanzabum

Without the ability to measure, it would be difficult for scientists to conduct experiments or form theories. Not only is measurement important in science and the chemical industry, it is also essential in farming, engineering, construction, manufacturing, commerce, and numerous other occupations and activities.

5 0

4 years ago

Read 2 more answers

Two objects each with a mass of 5x10^15 kg have a gravitational

kipiarov [429]

Answer:

Distance, r = 700.31 m

Explanation:

Mass of two objects, $m_1=m_2=5\times 10^{15}\ kg$

Force between the objects , $F=3.4\times 10^{15}\ N$

We need to find the distance between the two objects. The force of gravitational between two objects is given by :

$F=G\dfrac{m_1m_2}{r^2}\\\\r=\sqrt{\dfrac{Gm_1m_2}{F}} \\\\r=\sqrt{\dfrac{6.67\times 10^{-11}\times (5\times 10^{15})^2}{3.4\times 10^{15}}}\\\\=700.31\ m$