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2 years ago

What is power the quotient of?

Physics

1 answer:

kobusy [5.1K]2 years ago

4 0

<h2>Physics</h2>

Power quotient of : _____?

Answer :

$p = \frac{w}{t}$

P is Power (Watt)

W is Work (Joule)

T is Time (second)

So, it means Work and Time is the quotient of Power. (B)

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Does this marble have potential energy?<br> 1) no<br> 2)yes

jek_recluse [69]

Answer:

yes

Explanation:

because it has the potential to move

5 0

3 years ago

Thylakoids contain chlorophyl that absorb solar energy

steposvetlana [31]

Answer:

True

True statement:

Because pigment molecules absorb solar energy and thylakoids are pigment molecules

3 0

2 years ago

What is the resistance of : A) A 1.70 m long copper wire that is 0.700 mm in diameter? B) A 20.0 cm long piece of carbon with a

astra-53 [7]

Answer:

(I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

Explanation:

Given that,

Length of copper wire = 1.70 m

Diameter = 0.700 mm

Length of carbon piece = 20.0 cm

Cross section area $A = (2.00\times10^{-3})^2\ m$

(I). We need to calculate the area of copper wire

Using formula of area

$A=\pi r^2$

$A=3.14\times(\dfrac{0.700\times10^{-3}}{2})^2$

We need to calculate the resistance

Using formula of resistance

$R=\dfrac{\rho l}{A}$

Put the value into the formula

$R=\dfrac{1.68\times10^{-8}\times1.70}{3.14\times(\dfrac{0.700\times10^{-3}}{2})^2}$

$R=0.0742\ \Omega$

(II). We need to calculate the resistance

Using formula of resistance

$R=\dfrac{\rho l}{A}$

Put the value into the formula

$R=\dfrac{3.5\times10^{-5}\times20\times10^{-2}}{(2.00\times10^{-3})^2}$

$R=1.75\ \Omega$

Hence, (I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

8 0

3 years ago

Explain the difference between the synodic period of a planet and the sidereal period. why is the synodic period often much less

Ilia_Sergeevich [38]

-Synodic period is the period of celestial bodies observed on the moving planet(mostly earth)
Sideral period is the period comparing to the fixed stars without motion of the earth involved.

(I will explain the second question with an example, so it's easier to understand)
-For Sideral month for example of the moon it cactually complete one revolution in around 27.3 days.
However, since the earth moves, for us it took some more time to see the moon the same as before (fullmoon to fullmoon) again. That make synodic month of the moon to be around 29.5 days.

4 0

3 years ago

Which statement correctly compares infrared light to ultra violet light

mrs_skeptik [129]

What are the statements?

3 0

2 years ago