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Marianna [84]
3 years ago
7

What is power the quotient of?

Physics
1 answer:
kobusy [5.1K]3 years ago
4 0
<h2>Physics</h2>

Power quotient of : _____?

Answer :

p  =   \frac{w}{t}

P is Power (Watt)

W is Work (Joule)

T is Time (second)

So, it means Work and Time is the quotient of Power. (B)

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What combination of things happen on earth that helps make wind, and the weather on earth? (Please list at least two factors, an
Westkost [7]

Answer:

There are six main components, or parts, of weather. They are <u>temperature, atmospheric pressure, wind, humidity, precipitation, and cloudiness</u>. Together, these components describe the weather at any given time. These changing components, along with the knowledge of atmospheric processes, help meteorologists—scientists who study weather—forecast what the weather will be in the near future.

8 0
2 years ago
a body initially at rest, starts moving with a constant acceleration of 2ms-2 .calculate the velocity acquired and the distance
Marta_Voda [28]

a) 10 m/s

b) 25 m

Explanation:

a)

The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:

v=u+at

where

u is the initial velocity

v is the final velocity

a is the acceleration

t is the time

For the body in this problem:

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

t = 5 s is the time

So, the final velocity is

v=0+(2)(5)=10 m/s

b)

In this second part, we want to calculate the distance travelled by the body.

We can do it by using another suvat equation:

v^2-u^2=2as

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the distance travelled

Here we have

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

v = 10 m/s is the final velocity

Solving for s,

s=\frac{10^2-0^2}{2(2)}=25 m

3 0
3 years ago
A flea jumps by exerting a force of 1.07 10-5 N straight down on the ground. A breeze blowing on the flea parallel to the ground
Aleonysh [2.5K]

Answer:

a) 15.77 m/sec2

b) 13.3 deg

Explanation:

we are given;

Flea force = F1=1.07×10⁻5 N j

Breeze force = F2 = 1.14× 10⁻6 N (-j

mass of flea =6.0 ×10⁻7 kg

So net force on the flea=F1+F2+weight of flea=1.07×10⁻5 j +1.14× 10⁻6 i + 6.0 ×10⁻7 (-j) ×9.8= ma

==> ma = 1.07×10⁻5 j - 0.588×10⁻5 j + 0.114×10⁻5 i

==> ma= 0.482 ×10⁻5 j +0.114×10⁻5 i

==> ma = 0.114×10⁻5 i +0.482 ×10⁻5 j

== a = (0.114×10⁻5 i +0.482 ×10⁻5 j) / 6.0 ×10⁻7

==> a =

==>a= (1.9 j+8.03 i ) m/sec2

mag of a \sqrt{1.9^{2}  +8.03^{2} = 15.77 m/sec2

direction angle = tan⁻1(1.9/8.03)=13.3°

8 0
3 years ago
A 2.00-kg ball is moving at 2.20 m/s toward the right. It collides elastically with a 4.00-kg ball that is initially at rest. 1)
loris [4]
Elastic collision is when kinetic energy before = kinetic energy after

Ek= 1/2mv^2

total before
Ek=1/2(2)(2.2^2) = 4.84 J

total after
Ek= 1/2(2+4)(v^2) = 3v^2

Before = after
4.84=3v^2 | divide by 3
121/75 = v^2 | square root both sides
v=1.27 m/s
7 0
3 years ago
A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 11 m from the takeoff point. part a if the
Svetllana [295]
We have that the maximum rank of the kangaroo is given by:
 R = v0 ^ 2 sin (2θ) / g
 where,
 v0 = initial velocity
 θ = angle of the velocity vector formed from the horizontal
 g = gravity
 Clearing the speed we have:
 v0 ^ 2 = (R * g) / (sin (2θ))
 Substituting values
 v0 = root (((11) * (9.8)) / (sin (2 (21 * (pi / 180)))))
 v0 = 12.69 m / s
 answer
 its takeoff speed is 12.69 m / s
6 0
3 years ago
Read 2 more answers
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