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OLEGan [10]
2 years ago
10

Which pair does NOT have an electric force between them?.

Physics
1 answer:
viva [34]2 years ago
5 0

Two neutral objects will not have any electric force of attraction or repulsion between them.

<h3>What is the condition for the electric force between two objects?</h3>

As we know from the electrostatics that whenever there are two charges having a positive charge on one and a negative on the other will attract each other

similarly, if they are having like charges which are both of them having positive or both of them having a negative charge then there will be a force of repulsion between them.

But if both of them or even one of them is neutral then there will not be any electric force between them.

Thus neutral objects will not have any electric force of attraction or repulsion between them.

To know more about the nature of charged particles follow

brainly.com/question/22492496

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Singing that is off-pitch by more than about 1% sounds bad. How fast would a singer have to be moving relative to the rest of a
Nina [5.8K]

Answer:

-3.396 m/s or 3.465 m/s

Explanation:

v = Speed of sound in air = 343 m/s

v_s = Relative speed of the singer

f = Observed frequency

f' = Actual frequency

1% change can mean f=1.01f'

From the Doppler effect equation we have

f=f'\dfrac{v}{v+v_s}\\\Rightarrow 1.01f'=f'\dfrac{v}{v+v_s}\\\Rightarrow 1.01=\dfrac{343}{343+v_s}\\\Rightarrow v_s=\dfrac{343}{1.01}-343\\\Rightarrow v_s=-3.396\ m/s

The velocity is -3.396 m/s

when f=0.99f'

f=f'\dfrac{v}{v+v_s}\\\Rightarrow 0.99f'=f'\dfrac{v}{v+v_s}\\\Rightarrow 0.99=\dfrac{343}{343+v_s}\\\Rightarrow v_s=\dfrac{343}{0.99}-343\\\Rightarrow v_s=3.46464646465\ m/s

The velocity is 3.465 m/s

3 0
3 years ago
The pirate ship tie at the amusement park is a giant pendulum that riders sit in. It swings back and forth, with a maximum veloc
kkurt [141]

Here as we know that there is no loss of energy

so we can say that maximum kinetic energy will become gravitational potential energy at its maximum height

So here we have

\frac{1}{2}mv^2 = mgh

here we have

v = 20 m/s

m = 8000 kg

now from above equation we have

\frac{1}{2}(8000)(20^2) = (8000)(9.8)h

h = \frac{200}{9.8)

h = 20.4 m

so maximum height is 20.4 m

4 0
3 years ago
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The weightlifter's internal store of energy decreased when he lifted the bar.
Mumz [18]

Answer:

The energy returns to the weightlifter's muscles, where it is dissipated as heat.

Explanation:

The energy returns to the weightlifter's muscles, where it is dissipated as heat. As long as the weightlifter controls the weight's descent, their muscles are acting as an overdamped shock absorber, as if the weight were sitting on a piston containing very thick fluid, slowly compressing it downward (and slightly heating up the fluid in the process). Since muscles are complicated biological systems and not simple pistons, they require metabolic energy to maintain tension throughout the controlled descent, so the weightlifter feels like they're putting energy into the weight, even though the weight's gravitational potential energy is being converted into heat within the lifter's muscles.

5 0
3 years ago
An asteroid orbiting the Sun has a mass of 4.00×1016 kg. At a particular instant, it experiences a gravitational force of 3.14×1
Ksivusya [100]
<h2>The asteroid is 4.11 x 10¹¹ m far from Sun</h2>

Explanation:

We have gravitational force

                 F=\frac{GMm}{r^2}

           Where G =  6.67 x 10⁻¹¹ N m²/kg²

                       M = Mass of body 1

                       M = Mass of body 2

                       r = Distance between them

Here we have

                 M = Mass of Sun = 1.99×10³⁰ kg

                 m = Mass of asteroid = 4.00×10¹⁶ kg

                 F = 3.14×10¹³ N

Substituting

                   F=\frac{GMm}{r^2}\\\\3.14\times 10^{13}=\frac{6.67\times 10^{-11}\times 1.99\times 10^{30}\times 4\times 10^{16}}{r^2}\\\\r=4.11\times 10^{11}m

The asteroid is 4.11 x 10¹¹ m far from Sun

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An engineer is investigating potential energy with two
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Answer:

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