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Rina8888 [55]
3 years ago
8

Alex pushes on a 2.0 kg book, resulting in a net force of 6.0 N on the book.

Physics
1 answer:
Yakvenalex [24]3 years ago
4 0

Answer:

<h2>3.0 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a  = \frac{f}{m}  \\

From the question we have

a =  \frac{6}{2}  \\

We have the final answer as

<h3>3.0 m/s²</h3>

Hope this helps you

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Find the resultant of an easterly force of 100 N and a southeast force of 80 N acting at 65 degrees to the 100 N force
saveliy_v [14]

Answer:

Resultant is 152 N at 28.5 degrees south to the 100 N force

Explanation:

7 0
3 years ago
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Yanka [14]

Answer:

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4 0
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Complete each statement with the word that makes it true.
Nuetrik [128]

Answer:

reactive

halogens

nonmetals

Explanation:

5 0
2 years ago
Calculate the magnitude of the force exerted by each wire on a 1.20-m length of the other.
Zielflug [23.3K]

Incomplete question.The complete question is attached below as screenshot along with figure

Answer:

F=6.00*10^{-6}N

Force is repulsive

Explanation:

Given data

Current I₁=5.00A

Current I₂=2.00A

Length L=1.20 m

Radius r=0.400m

To find

Force F

Solution

As the force is repulsive because currents are in opposite direction

From repulsive force we know that:

F=\frac{u_{o}I_{1}I_{2}L}{2\pi r}

Substitute the given values

F=\frac{u_{o}(5.00A)(2.00A)(1.20m)}{2\pi (0.400m)}\\ F=6.00*10^{-6}N

4 0
2 years ago
You are driving along a highway at 35.0 m/s when you hear the siren of a police car approaching you from behind and you perceive
padilas [110]

Answer:

f_{police}=1268.7 Hz    

Explanation:

We can use Doppler equation to find the frequency of the siren.

First of all we have the police car moving behind the car. Hence, the frequency detected by the car will be:  

f_{car1}=f_{police}(\frac{v_{s}-v_{car}}{v_{s}-v_{police}})      (1)

Now, when the police car is moving in front of the car, the frequency detected by the car will be:

f_{car2}=f_{police}(\frac{v_{s}+v_{car}}{v_{s}+v_{police}})        (2)            

By solving equation (1) and equation (2) for v_{police} we have:

v_{police} = 44.67 m/s

Knowing that:

  • f(car1) = 1310 Hz
  • f(car2) = 1240 Hz
  • Vs = 343 m/s
  • V(car) = 35 m/s

Finally, we just need to put this value into the first equation to find frequency of the police car.

f_{police}=f_{car}(\frac{v_{s}-v_{police}}{v_{s}-v_{car}})    

f_{police}=1310(\frac{343-44.7}{343-35})  

f_{police}=1268.7 Hz    

I hope it helps you!

                                                                                                                                       

7 0
2 years ago
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