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Talja [164]
3 years ago
10

Csggggresddgdfgthxefecdtvh

Physics
2 answers:
Inessa05 [86]3 years ago
8 0

Answer:

csggggresdd

...........

SOVA2 [1]3 years ago
3 0

Answer:

yes :)

Explanation:

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A skateboarder skates down a ramp for 3 seconds. If his initial velocity was 0.8 m/s and · his final velocity was 7 m/s, what wa
Contact [7]

Answer:

The acceleration of the skateboarder is 2.067 m/s²

Explanation:

Given;

initial velocity of the  skateboarder, u = 0.8 m/s

final velocity of the  skateboarder, v = 7 m/s

time of motion, t = 3 s

The acceleration of the skateboarder is given as;

a = \frac{v-u}{t}\\\\a = \frac{7-0.8}{3}\\\\a = 2.067   \ m/s^2

Therefore, the acceleration of the skateboarder is 2.067 m/s²

5 0
3 years ago
A pump lifts water from a lake to a large tank 20 m above the lake. How much work against gravity does the pump do as it transfe
Aleonysh [2.5K]

Answer:

980 kJ

Explanation:

Work = change in energy

W = mgh

W = (1000 kg/m³ × 5.0 m³) (9.8 m/s²) (20 m)

W = 980,000 J

W = 980 kJ

The pump does 980 kJ of work.

3 0
3 years ago
Read 2 more answers
Benjamin recently issued new mobile phones to the marketing team at his company. Each phone can transmit encrypted information f
Misha Larkins [42]

Complete Question:

Which technology is set up on the marketing team's phones?

a) Bluetooth

b) Tethering

c) NFC

d) Hotspot

Answer:

NFC

Explanation:

Near Field Communication (NFC) is a short-range wireless connectivity standard that uses magnetic field induction to enable communication between devices when  brought within a few centimetres from each other. NFC offers a secured communication between connected electronic devices with simple setup that can be used to bootstrap more-capable wireless connections. It only covers a range of 10 cm to 20 cm.

None of the other options can transmit or share information for payments among the team except the NFC. NFC is also suitable for this setup because only a small range is expected to be covered.

4 0
3 years ago
If the dielectric constant is 14.1, calculate the ratio of the charge on the capacitor with the dielectric after it is inserted
Lady bird [3.3K]

Answer:

\frac{Q}{Q_0}=1

Explanation:

Capacitance is defined as the charge divided in voltage.

C=\frac{Q}{V}(1)

Introducing a dielectric into a parallel plate capacitor decreases its electric field. Therefore, the voltage decreases, as follows:

V=\frac{V_0}{k}

Where k is the dielectric constant and V_0 the voltage of the capacitor without a dielectric

The capacitance with a dielectric between the capacitor plates is given by:

C=kC_0

Where k is the dielectric constant and C_0 the capacitance of the capacitor without a dielectric. So, we have:

Q=CV\\Q=kC_0\frac{V_0}{k}\\Q=C_0V_0\\Q_0=C_0V_0\\Q=Q_0\\\frac{Q}{Q_0}=1

Therefore, a capacitor with a dielectric stores the same charge as one without a dielectric.

7 0
3 years ago
A parallel beam of light from a laser with a wavelength 450 nm, falls on a grating whose slits are 1.28 x 10^-4 cm apart. How fa
Katena32 [7]

Answer:

Y_1 = 1.195 m = 119.5 cm

Explanation:

For nth order bright fringe, the distance from the center of the pattern is given by :-

Y_n = \frac{n\lambda D}{d}.

Where,

n = order of nth  bright fringe. = 1

\lambda = wavelength of  given light  =  450 nm = 450*10-{9} m

D = distance between the screen and slits. =  3.4 m

and d = separation between the slits. = 1.28 *10^{-4} cm =1.28 *10^{-6} m

Y_1 = \frac{(1 *450 *10{-9} *3.4)}{(1.28*10{-6})}

Y_1 = 1.195 m = 119.5 cm

7 0
3 years ago
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