How do clouds affect solar energy (radiation)?

When hydrochloric acid is poured over potassium sulfide, 42.5 mL of hydrogen sulfide gas is produced at a pressure of 756 torr a

EastWind [94]

<h2>Answer:</h2> $0.1899grams$

<h2>Explanations:</h2>

The balanced chemical reaction between hydrochloric acid and potassium sulfide is as shown:

$K_2S+2HCl\to H_2S+2KCl$

Based on stoichiometry, we can see that 1 mole of potassium sulfide reacted to form 1 mole of hydrogen sulfide.

Get the mole of hydrogen sulfide gas (H2S) using the ideal gas equation expressed as:

$\begin{gathered} PV=\text{nRT} \\ n=\frac{PV}{RT} \end{gathered}$

P is the pressure of the gas (in atm) = 0.994737atm (756torr)

V is the volume of the gas = 42.5mL = 0.0425L

T is the temperature (in Kelvin) = 26 + 273 = 299K

R is the gas constant = 0.0821 L*atm/mole * K

Substitute these values into the formula as shown:

$\begin{gathered} n=\frac{0.994737\cancel{\text{atm}}\times0.0425\cancel{L}}{0.0821\frac{\cancel{L}\cdot\cancel{\text{atm}}}{\text{mole}\cdot\cancel{K}}\times299\cancel{K}} \\ n=\frac{0.994737\times0.0425}{0.0821\times299} \\ n=\frac{0.0422763225}{24.5479} \\ n=0.00172\text{moles} \end{gathered}$

Since the number of moles of hydrogen sulfide is 0.00172moles, the number of moles of potassium sulfide will also be 0.00172 moles (based on stoichiometry)

Get the mass of potassium sulfide that reacted using the formula:

$\text{Mass}=number\text{ of moles}\times molar\text{ mass}$

Number of moles of K2S = 0.00172 moles

Molar mass of K2S = 110.262 g/mol

Substitute into the formula for calculating the mass;

$\begin{gathered} \text{Mass}=0.00172\cancel{\text{moles}}\times\frac{110.262g}{\cancel{\text{mole}}} \\ \text{Mass}=0.1899\text{grams} \end{gathered}$

Therefore the mass of potassium sulfide that reacted (in grams) is approximately 0.1899grams

3 0

1 year ago

Which group of archaea are chemoautotrophic anaerobes that use hydrogen as an electron donor and sulfur compounds as terminal el

vodomira [7]

The group of archaea that are chemoautotrophic anaerobes that use hydrogen as an electron donor and sulfur compounds as terminal electron acceptors are the

Thermoacidophiles.

<h3>What are chemoautotrophic anaerobes?</h3>

The chemoautotrophic anaerobes are those organisms that derive energy for survival through the reduction of the following compounds:

CO2 to CH4, or

SO4 to H2S.

Thermoacidophiles is a typical example of the group of archaea that are chemoautotrophic anaerobes that use hydrogen as an electron donor and sulfur compounds as terminal electron acceptors.

Learn more about anaerobes here:

brainly.com/question/16188326

#SPJ1

7 0

2 years ago

Calculate the H3O+ concentration and then pH in a 0.100 M HC2H3O2 solution that is

Lana71 [14]

Answer:

Please check with the attachment posted.

Please do confirm the answer.

5 0

3 years ago

1. Identify the two types of outline.<br>

ZanzabumX [31]

What do you mean.. ...

3 0

3 years ago

The equation for the reaction, BaCl2(aq) + K2CrO4(aq) → BaCrO4(s) + KCl(aq), can be written as an ionic equation. In the ionic e

Arturiano [62]

Answer:

The Cl⁻ and K⁺ are spectator ions.

Explanation:

Balanced Chemical equation:

BaCl₂(aq) + K₂CrO₄(aq) → BaCrO₄(s) + 2KCl (aq)

Ionic equation:

Ba²⁺(aq) + 2Cl⁻(aq) + 2K⁺(aq) + CrO₄²⁻(aq) → BaCrO₄(s) + 2k⁺(aq) + 2Cl⁻ (aq)

Net ionic equation:

Ba²⁺(aq) + CrO₄²⁻(aq) → BaCrO₄(s)

The Cl⁻ and K⁺ are spectator ions that's why these are not written in net ionic equation. The BaCrO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

8 0

3 years ago