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Lena [83]
2 years ago
11

Write the nuclear equation for each of the following reactions. Refer to a periodic table.

Chemistry
1 answer:
labwork [276]2 years ago
5 0

Answer:

a. 226/88Ra --> 222/86Rn + 4/2He

Explanation:

Alpha decay you lose four from the mass number and two from the Atomic number. Giving you 222 mass and 86 atomic. Radon has 222 mass and 86 atomic 222/86Rn + the four from the mass we took and the two from the atomic we took. What element has 4 mass and 2 atomic. Helium 4/2He  

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B.Elements

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Explanation:

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Explain why Nitrogen -17 is unstable
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2 years ago
What volume is occupied by 0.109 molmol of helium gas at a pressure of 0.98 atmatm and a temperature of 307 K
KATRIN_1 [288]

Answer:

2.8 L

Explanation:

From the question given above, the following data were obtained:

Number of mole (n) = 0.109 mole

Pressure (P) = 0.98 atm

Temperature (T) = 307 K

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

The volume of the helium gas can be obtained by using the ideal gas equation as follow:

PV = nRT

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0.98 × V = 2.7473123

Divide both side by 0.98

V = 2.7473123 / 0.98

V = 2.8 L

Thus, the volume of the helium gas is 2.8 L.

6 0
3 years ago
How do I calculate the standard enthalpy change for the following reaction at 25 °C ?
ladessa [460]
MgCl2(s) + H2O(l) → MgO(s) + 2 HCl(g) 

Using the standard enthalpies of formation given in the source below: 

(−601.24 kJ) + (2 x −92.30 kJ) − (−641.8 kJ) − (−285.8 kJ) = +141.76 kJ 
So: 

MgCl2(s) + H2O(l) → MgO(s) + 2 HCl(g), ΔH = +141.76 kJ
4 0
4 years ago
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