The period of the pendulum is 6 seconds.
<h3>What is period?</h3>
Period is the time taken for a simple pendulum to move to(forward) and fro(backward). The s.i unit of period is seconds(s).
Note: When a simple pendulum moves to and fro. it completes one cycle.
From the question, The period of the pendulum is calculated using the formula below.
<h3>Formula</h3>
- T = a+b.............. Equation 1
Where:
- T = Period of the pendulum
- a = Time taken for the pendulum to move forward
- b = Time taken for the pendulum to move backward.
From the question,
Given:
Substitute the values above into equation 1
Hence, The period of the pendulum is 6 seconds.
Learn more about period here: brainly.com/question/21924087
Answer:
B = 4.323 T
Explanation:
We are given;
Inner radius; r_i = 0.7 m
Number of turns; N = 890 turns
Current; I = 17 KA = 17000 A
Formula for the magnetic field inside the toroid along the inner radius is given by;
B = (μ_o × N × I)/(2πr)
μ_o is vacuum of permeability with a constant value of 4π × 10^(-7) H/m
Plugging in the relevant values, we have;
B = (4π × 10^(-7) × 890 × 17000)/(2 × π × 0.7)
B = (2 × 10^(-7) × 890 × 17000)/(0.7)
B = 4.323 T
Answer:
the final velocity of the car is 59.33 m/s [N]
Explanation:
Given;
acceleration of the car, a = 13 m/s²
initial velocity of the car, u = 120 km/h = 33.33 m/s
duration of the car motion, t = 2 s
The final velocity of the car in the same direction is calculated as follows;
v = u + at
where;
v is the final velocity of the car
v = 33.33 + (13 x 2)
v = 59.33 m/s [N]
Therefore, the final velocity of the car is 59.33 m/s [N]
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Kinetic energy is equivalent to .5*(mass)*(velocity)^2
The mass should be in kilo grams and the velocity in meters per second.
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