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Mandarinka [93]
2 years ago
13

What is the percentage of water in the following compound? answer using one decimal place. sodium carbonate decahydrate, na2co3

• 10h2o % by mass h2o
Chemistry
2 answers:
ehidna [41]2 years ago
6 0

The percentage by mass of water in Na2CO3.10H2O from the calculation is  62.9%

<h3>What is percentage by mass?</h3>

The term percentage by mass refers to the amount of a particular moiety by mass in a molecule.

In this case, we know that the molar mass of Na2CO3.10H2O is 286 g/mol the molar mass of the 10 moles of water is 180 g/mol hence the percentage by mass of water in the compound is; 180 g/mol /286 g/mol  * 100/1 = 62.9%

Learn more about percentage by mass: brainly.com/question/16885872

#SPJ2

vaieri [72.5K]2 years ago
4 0

Answer:

63.0

Explanation:

got it wrong so it told me the answer

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Answer:

  • <u>Option b. Atom P has an estimated Zeff of 7 and is therefore to the right of Atom Q, which has a Zeff of 6.</u>

Explanation:

Please, find attached the figures of both atom Q and atom P corresponding to this question.

The <u>features of atom Q are</u>:

  • Each <em>black sphere</em> represents an electron
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  • <em>Zeff </em>is the effective nuclear charge of the atom. It accounts for the  net positive charge the valence electrons experience. And may, in a very roughly way, be estimated as the number of protons less the number of electrons in the inner shells. Thus, for this atom, an estimated  Z eff = 8 - 2 = 6.

The <u>features of atom P</u> are:

  • Again, each black sphere represents an electron
  • In total this atom has 9 electrons: 2 in the inner shell and 7 in the outermost shell.
  • Since it is assumed that the atom is neutral, it has 9 protons.
  • The atomic number of this atom is 9.
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Then, since atom P has a greater Z eff than atom Q (an estimated Zeff of 7 for atom P against an estimated Z eff of 6 for atom Q),  and both atoms are in the same period, you can affirm that <em>atom P</em> has a greater atomic number and<em> is therefore to the right of atom Q</em>.

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