1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
azamat
3 years ago
13

Consider the reaction in chemical equilibrium. cocl2(g) co(g) + cl2(g) which is the correct equation for k?

Chemistry
2 answers:
hichkok12 [17]3 years ago
8 0
K=[CO][Cl^2] / [COCl^2]
Sergeu [11.5K]3 years ago
3 0

Answer:

Keq = \frac{P_{CO}*P_{Cl2}  }{P_{COCl2} }

Explanation:

A reaction is said to be at equilibrium when the rate of consumption of reactants equals the rate of formation of products. This state can be depicted in terms of the equilibrium constant (Keq) which is essentially the ratio of concentration (or pressure for gases) of the products to that of the reactants each of which is raised to an appropriate coefficient defined by the balanced chemical equation.

Keq = \frac{[Products]}{[Reactants]}

The given reaction is:

cocl2(g) ↔ co(g) + cl2(g)

Keq = \frac{P_{CO}*P_{Cl2}  }{P_{COCl2} }

Here the Keq is given in terms of the partial pressure of the gases

You might be interested in
why do liquids flow? the particles are tightly packed together the particles do not move the particles vibrate the particles are
tangare [24]
The particles are quite tightly packed together but still have enough room to be able to move and flow, their bonds aren't as strong as a solids are
3 0
2 years ago
Need these 2 answered asap pls
Kitty [74]

Answer:

im not a brain wiz but i think 20

Explanation:

3 0
3 years ago
A nugget of gold has a mass of 28 grams and a volume of 1.45 cubic centimeters. What is the density?
Travka [436]

Answer:

0.01931034

Explanation:

Steps:

ρ =  m/v

       =  

28 gram

1.45 cubic meter

=  19.310344827586 gram/cubic meter

=  0.019310344827586 kilogram/cubic meter

7 0
2 years ago
When ethyl-2-methylpropanoate is treated with sodium ethoxide in ethanol, there is no observable reaction. Explain this observat
den301095 [7]

Answer:

No net change in reaction occurs in this nucleophilic acyl subtitution reaction

Explanation:

Sodium ethoxide in ethanol gives nucleophilic acyl substitution reaction with ethyl-2-methylpropanoate.

Here ethoxide group replaces an ethoxide group from ester through addition-ellimination pathway.

So, ultimately, the product of this reaction is identical with reactant i.e. ethyl-2-methylpropanoate is reproduced.

Hence one might observe no change during reaction as product and reactant of this reaction are same.

Mechanistic pathway has been shown below.

8 0
3 years ago
In carbon dioxide (CO2), there are two oxygen atoms for each carbon atom. Each oxygen atom forms a double bond with carbon, so t
katrin2010 [14]

Answer: D) Eight

Just pretend this part doesn't exist nope nothing to see here the answer is correct on edge2020 I swear on my brainly points

4 0
3 years ago
Read 2 more answers
Other questions:
  • Explain why heat is often used in a laboratory experiment. a. To warm up the laboratory, b. To speed up a reaction
    10·1 answer
  • What would be the concentration of a solution resulting when you dissolve 4.725g of nacl (molar mass = 58.45) in water to make a
    10·1 answer
  • What makes an element inert?
    12·1 answer
  • What causes liquids to conduct electricity?
    9·1 answer
  • How long will it take for a 750 mg sample of radium with a half life of 15 days to decay to exactly 68mg?
    10·1 answer
  • The initial movement of groundwater into the atmosphere to form clouds is due to what?
    9·2 answers
  • Classify this reaction: 2Al+N2->AlN.
    11·1 answer
  • Select the two statements that are TRUE about compounds
    8·1 answer
  • In a chemical formula or a chemical equation, what is the small number after the element symbol? ​
    8·1 answer
  • What is obesity and hemoglobin?​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!