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azamat
3 years ago
13

Consider the reaction in chemical equilibrium. cocl2(g) co(g) + cl2(g) which is the correct equation for k?

Chemistry
2 answers:
hichkok12 [17]3 years ago
8 0
K=[CO][Cl^2] / [COCl^2]
Sergeu [11.5K]3 years ago
3 0

Answer:

Keq = \frac{P_{CO}*P_{Cl2}  }{P_{COCl2} }

Explanation:

A reaction is said to be at equilibrium when the rate of consumption of reactants equals the rate of formation of products. This state can be depicted in terms of the equilibrium constant (Keq) which is essentially the ratio of concentration (or pressure for gases) of the products to that of the reactants each of which is raised to an appropriate coefficient defined by the balanced chemical equation.

Keq = \frac{[Products]}{[Reactants]}

The given reaction is:

cocl2(g) ↔ co(g) + cl2(g)

Keq = \frac{P_{CO}*P_{Cl2}  }{P_{COCl2} }

Here the Keq is given in terms of the partial pressure of the gases

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what volume of ethylene gas at 293K and 102kPa must be compressed to yield 295m3 of ethylene gas at 808kPa and 585K​
luda_lava [24]
<h3>Answer:</h3>

1170.43 m³

<h3>Explanation:</h3>

<u>We are given;</u>

  • Initial pressure, P1 as 808 kPa
  • Initial temperature, T1 as 585 K
  • Initial volume, V1 as 295 m³
  • New pressure, P2 as 102 kPa
  • New temperature, T2 as 293 K

We are required to find the new volume;

  • We are going to use the combined gas law
  • According to the gas law;  \frac{P1V1}{T1}=\frac{P2V2}{T2}
  • Thus, rearranging the formula;

V2=\frac{P1V1T2}{P2T1}

V2=\frac{(808 kPa)(295)(293K)}{(102 kPa)(585K)}

V2=1170.43

Therefore, the volume is 1170.43 m³

6 0
3 years ago
What are twoparts of an atom
Leto [7]
The answer is neutrons and protons.

Hope you got it!!
6 0
3 years ago
What is meant by the limiting reactant why is it necessary to identify the limiting reactant when you want to know what?
WARRIOR [948]

You have the reactants who react to make your products.

Reactants --------> Products

The limiting reactant is the reactant that will RUN OUT FIRST and that will establish the maximum amount of product that will be produced.

To make an example, let's look at this equation and at the following question:

2Al + 6HCl → 2AlCl3 + 3H2

When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed?

We know that 2Al + 6HCL are the reactants, right?

These 2 reactants will react to create an amount of a certain product in this case they're asking us for the amount of H2 that will be produced. Therefore, we need to find the REACTANT it can be either AL OR HCL.

But, how do we know which one is the limiting reactant?

To know which one is the limiting reactant we need to know HOW MUCH H2 can Al produce, and also how much H2 can HCL produce. Why?

It's simple, because if you find the one that produces the less amount of H2, you know immediately that's the maximum amount of that product that will be produced.

Let's say you have a sandwich that needs to be made with 2 slices of bread, 3 meats and 1 cheese.

But you have got 4 slices of bread, 9 slices of meat, and 5 slices of cheese.

Well, you could make 2 sandwiches with 4 slices of bread, 3 sandwiches with those 9 slices of meat and 5 sandwiches with the 5 slices of cheese.

But, in reality, you can only make 2 sandwiches because you don't have any more bread to produce more sandwiches. You get it? That is the point of limiting reactants, to find what is the actual amount that can be produced.

Coming back to our equation, we can find the number of moles of H2 produced by each one of the reactants, Al and HCl. I'll find the number of moles quickly to show you what the concept of limiting reactant is.

6.0mol Al x 3 mol H2/2 mol Al = 9 mol H2

13 mol HCL x 3 mol H2/6 mol HCL = 6.5 mol H2

As you can see, 6.5 mol of H2 is the maximum that can be produced by the HCL and is less than the Al, so that maximum amount that you will get in the product H2 is no more than 6.5.

4 0
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A certain sample of a liquid has a mass of 42 grams and a volume of 35 centimeters3. What is the density of the liquid? The dens
Xelga [282]

Density of liquid= \frac{mass of liquid}{volume of liquid}.

so, density of liquid= \frac{42 gm}{35 cm^{3} }= 1.2 gm/cm³.

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