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Zanzabum
2 years ago
10

Why do we use the metric system in science?

Chemistry
1 answer:
disa [49]2 years ago
8 0

we use the metric system in science just for the simple fact that it is a common unit practice around the world. in science we must use the same system, because it would cause confusion or mistakes.

hope this helps good luck! :)

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What is most likely to happen when two fluorine atoms bond?
alina1380 [7]

Answer:

A nonpolar covalent bond

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3 years ago
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A gas cylinder contains exactly 15 moles of oxygen gas (O2). How many molecules of oxygen are in the cylinder? 4.01 × 1022 molec
Semmy [17]
The answer is 9.03 × 10²⁴<span> molecules.

</span><span>Avogadro's number is the number of units (atoms, molecules) in 1 mole of substance.
Make the proportion.
</span><span>6.02 × 10²³ molecules per 1 mol
</span>x per 15 mol

6.02 × 10²³ molecules : 1 mol = x : 15 mol
x = 6.02 × 10²³ molecules * 15 mol * 1 mol
x = 90.3 × 10²³ molecules
x = 9.03 × 10 × 10²³ molecules
x = 9.03 × 10²³⁺¹ molecules
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3 years ago
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Give the formula of the chlorine ion​
seraphim [82]

Answer:

fluorine plus chlorides think

3 0
3 years ago
what concentration in parts per million in a solution that contains .008 grams of o2 dissolved in 1000 grams of water
julia-pushkina [17]
Ppm = mass of solute mg / mass of solvent kg

0.008 * 1000 =  8.0 mg ( solute )

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ppm = 8 / 1

= 8.0 ppm

hope this helps!
7 0
3 years ago
The solubility of carbon dioxide in water is 0.161 g CO2in 100 mL of water at 20ºC and 1.00 atmCO2. A soft drink is carbonated w
Sedbober [7]

<u>Answer:</u> The solubility of carbon dioxide at 5.50 atm is 0.886g/100mL

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of carbon dioxide

C_2\text{ and }p_2 are the final concentration and partial pressure of carbon dioxide

We are given:

C_1=0.161g/100mL\\p_1=1.00atm\\C_2=?\\p_2=5.50atm

Putting values in above equation, we get:

\frac{0.161g/100mL}{C_2}=\frac{1.00atm}{5.50atm}\\\\C_2=\frac{0.161g/100mL\times 5.50atm}{1.00atm}=0.886g/100mL

Hence, the solubility of carbon dioxide at 5.50 atm is 0.886g/100mL

4 0
4 years ago
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