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kotegsom [21]
3 years ago
8

Pure ethylene glycol, , is added to 2.00 kg of water in the cooling system of a car. The vapor pressure of the water in the syst

em when the temperature is 90 °C is 451 mm Hg. What mass of glycol was added? (Assume the solution is ideal and ethylene glycol is nonvolatile. The vapor pressure of water at 90 °C is 525.8 mm Hg.)
Chemistry
1 answer:
spayn [35]3 years ago
6 0

Answer:

1367.7 g of ethylene glycol was added to the solution

Explanation:

In order to find out the mass of glycol we added, we apply the colligative property of lowering vapor pressure: ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent (P°) - Vapor pressure of solution(P')

525.8 mmHg - 451 mmHg = 451 mmHg . Xm

74.8 mmHg / 451 mmHg = Xm → 0.166 (mole fraction of solute)

Xm = Mole fraction of solute / Moles of solute + Moles of solvent

We can determine the moles of solvent → 2000 g . 1  mol/18 g = 111.1 mol

(Notice we converted the 2kg of water to g)

0.166 = Moles of solute / Moles of solute + 111.1 moles of solvent

0.166 (Moles of solute + 111.1 moles of solvent) = Moles of solute

18.4 moles = Moles of solute - 0.166 moles of solute

18.4 = 0.834 moles of solute → Moles of solute = 18.4/0.834 = 22.06 moles

Let's convert the moles to mass → 62 g/mol . 22.06 mol = 1367.7 g

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ivann1987 [24]
Grams ethanol = 33 ml times .789 gms/ml = 26.037 gms 

<span>Moles ethanol = 26.037 gms / 46 gms/mole = .57 moles </span>

<span>Moles water = 67 ml or 67 grams/18 gms/mole = 3.22 moles </span>

<span>total moles = .57 + 3.72 = 4.29 moles </span>

<span>Mole fraction ethanol = .57 moles ethanol / 4.29 moles total = 0.13</span>

<span>Moles fraction water = 3.72 moles water / 4.29 moles total = 0.87</span>

<span>Partial pressure of ethanol = mole fraction ethanol (.13) _ times VP ethanol 43.9 torr) = 5.707 torr </span>

<span>partial pressure water = mole fraction water .87) times VP water (l7.5 torr) = 15.23 torr </span>

<span>Total vapor pressure over solution = 5.71 torr + 15.23 torr = 20.94 torr</span>
7 0
3 years ago
When working with chemicals, a good practice to read about any safety ____ or actions that are taken to prevent harm
madreJ [45]

Answer:

Precautions

Explanation:(Grammar Check)

4 0
3 years ago
Cite 2 reasons Democritus’ ideas about the atom were NOT accepted
omeli [17]

The two reasons Democritus’ ideas about the atom were NOT accepted are atoms are indestructible and they move in infinite space.

<h3>What is atom?</h3>

An atom is the smallest unit of ordinary matter that forms a chemical element.

<h3>Democritus’ ideas about atom</h3>

Democritus believed that atoms were uniform, solid, hard, incompressible, and indestructible and that they moved in infinite numbers through empty space until stopped.

Differences in atomic shape and size determined the various properties of matter.

Thus, the two reasons Democritus’ ideas about the atom were NOT accepted are atoms are indestructible and they move in infinite space.

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4 0
2 years ago
What is the correct unabbreviated electron configuration of the following?:
Rudik [331]

The correct  unabbreviated electron configuration  is as below


Vanadium - 1S2 2S2 2P6 3S2 3p6 3d3 4s2

Strontium -  1s2 2S2 2P6 3S2 3P6 3d10 4S2 4P6 4S2

Carbon =1S2 2S2 2P2


<u><em> Explanation</em></u>

vanadium  is in atomic number  23  in the periodic table  hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d3 4s2

Strontium is in atomic number 38  in periodic table  hence  its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10  4s2 4p6 4s2

Carbon is in atomic number 6 in periodic  table  therefore its electron configuration is 1s2 2s2 2p2

5 0
4 years ago
The Following questions pertain to a 2.2M solution of hydrocyanic acid at 25°C. pKa = 9.21 at 25°C. Find the concentrations of a
horsena [70]
1) Chemical reaction: HCN + H₂O → CN⁻ + H₃O⁺.
c(HCN) = 2,2 M = 2,2 mol/L.
pKa(HCN) = 9,21.
Ka = 6,16·10⁻¹⁰.
[CN⁻] = [H₃O⁺] = x.
[HCN<span>] = 2,2 M - x.
</span>Ka = [CN⁻] · [H₃O⁺] / [HCN].
6,16·10⁻¹⁰ = x² / 2,2 M -x.
Solve quadratic equation: [CN⁻] = [H₃O⁺] = 0,0000346 M.
[HCN] = 2,2 M - 0,0000346 M = 2,199 M.

2) pH = - log[H₃O⁺].
pH = -log( 0,0000346 M).
pH = 4,46.
Hydrocyanic acid and hydronium ion (H₃O⁺) are acids. Cyanide anion (CN⁻) is the strongest base in the system, cyanide anion accept protons in chemical reaction.
pKb = pKw - pKa.
pKb = 14 - 9,21 = 4,79.

6 0
3 years ago
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