An unknown metal cylinder has a mass of 34.3 g and a volume of 2.1 mL . What is the density of the metal in g / m * L ?
1 answer:
Taking into account the definition of density, the density of the metal is 16.33 .
Density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.
<h3>Density of the metal in this case</h3>In this case, you know that:
- Mass= 34.3 g
- Volume= 2.1 mL
Replacing in the definition of density:
Solving:
<u><em>density= 16.33 </em></u>
In summary, the density of the metal is 16.33 .
Learn more about density:
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Moles of potassium permanganate = 0.0008
<h3>Further explanation </h3>Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range
Reaction
5Na2C2O4(aq) + 2KMnO4(aq) + 8H2SO4(aq) ---> 2MnSO4(aq) + K2SO4(aq) + 5Na2SO4(aq) + 10CO2(g) + 8H2O(1)
The end point ⇒titrant and analyte moles equal
titrant : potassium permanganate-KMnO4
analyte : sodium oxalate - Na2C2O4
so moles of KMnO4 = moles of Na2C2O4
moles of Na2C2O4(mass = 0.2640 g, MW=134 g/mol) :
From equation, mol ratio Na2C2O4 : KMnO4 = 5 : 2, so mol KMnO4 :