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Natasha_Volkova [10]
3 years ago
9

A certain first-order reaction is 27.5 percent complete in 8.90 min at 25°C. What is its rate constant?

Chemistry
1 answer:
jeyben [28]3 years ago
4 0

Answer:

k= 0.145min^{-1}

Explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us remember that the first-order kinetics is given by:

ln(A/A_0)=-kt

Whereas the 27.5% complete means A/Ao=0.275, and thus, we solve for the rate constant as follows:

k=\frac{ln(A/A_0)}{-t}

Then, we plug in the variables to obtain:

k=\frac{ln(0.275)}{-8.90min}\\\\k= 0.145min^{-1}

Regards!

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