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Umnica [9.8K]
2 years ago
10

at 25 C, 1.00 mole of O2 gas was found to occcupya volume of 12.5 L at a pressure of 198 kPa. What is the value of gas constant

in L•kPa/ mol•K
Chemistry
1 answer:
maw [93]2 years ago
8 0

Answer:

8.3

Explanation:

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The d-metals iron, copper, and manganese form cations with different oxidation states. For this reason, they are found in many o
choli [55]

Answer:

They have electrons in their 3d- and 4s-orbital for bond formation.

Explanation:

d- metals or transition metal are metal which form ion with partially filled d-orbital. Examples are iron and manganese.

The metals have 2 electrons in their 4s orbital. If only this is used for bonding, they will form compounds where they have oxidation State of +2 as seen in MnO.

If two 4s and one of 3d electrons are used, oxidation state of +3 is formed as seen in FeCl3.

If two 2s electron I used with two 3d electrons, compound with oxidation state of +4 is formed as seen in MnO2

4 0
3 years ago
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There are several ways to model a compound. One type
mr Goodwill [35]

Answer:

C4H9O2

Explanation:

there are 4 carbons, 9 hydrogens and 2 oxygens

6 0
3 years ago
Whats the answer to 7/2 × 1/5?​
svp [43]
The answer to the problem is 7/10
3 0
2 years ago
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1‑propanol ( n ‑propanol) and 2‑propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure a
Alex777 [14]

Answer:

y_{prop} = 0.134; y_{iso} = 0.866

The partial pressure of isopropanol = 34.04 Torr; The partial pressure of propanol = 5.26 Torr

Explanation:

For each of the solutions:

mole fraction of isopropanol  (x_{iso}) = 1 - mole fraction of propanol (x_{prop}).

Given: mole fraction of propanol = 0.247. Thus, the mole fraction of isopropanol = 1 - 0.247 = 0.753.

Furthermole, the partial pressure of isopropanol = x_{iso}*vapor pressure of isopropanol = 0.753*45.2 Torr = 34.04 Torr

The partial pressure of propanol = x_{prop}*vapor pressure of propanol = 0.247*20.9 Torr = 5.16 Torr

Similarly,

In the vapor phase,

The mole fraction of propanol (y_{prop}) = \frac{P_{prop} }{P_{prop}+P_{iso}}

Where, P_{prop} is the partial pressure of propanol and P_{iso} is the partial pressure of isopropanol.

Therefore,

y_{prop} = 5.26/(34.04+5.16) = 0.134

y_{iso} = 1 - 0.134 = 0.866

5 0
3 years ago
The density of aluminum is 2.70 g/mL. If you use 108 g of aluminum foil, what is its volume in mL?
Natali5045456 [20]

Answer:

volume =40.0 ml

Explanation:

density = mass/ volume

volume = mass/ density

volume = 108/ 2.70

volume =40.0 ml

3 0
2 years ago
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