Answer:
True
Explanation:
Matter can be in the form of a particle or a wave. This is known as the dual nature of matter. This concept was proposed by Louis de Broglie and was named after him. This phenomenon has been observed for all the elementary particles.
The de Broglie wavelength is given by

Where
h = Planck's constant
p = Particles momentum
m = Mass of particle
v = Velocity of particle
Answer:
False
Explanation:
When the location of the poles changes in the z-plane, the natural or resonant frequency (ω₀) changes which in turn changes the damped frequency (ωd) of the system.
As the poles of a 2nd-order discrete-time system moves away from the origin then natural frequency (ω₀) increases, which in turn increases damped oscillation frequency (ωd) of the system.
ωd = ω₀√(1 - ζ)
Where ζ is called damping ratio.
For small value of ζ
ωd ≈ ω₀
14 ms is required to reach the potential of 1500 V.
<u>Explanation:</u>
The current is measured as the amount of charge traveling per unit time. So the charge of electrons required for each current is determined as the product of current with time.

As two different current is passing at two different times, the net charge will be the different in current. So,

The electric voltage on the surface of cylinder can be obtained as the ratio of charge to the radius of the cylinder.

Here
, q is the charge and R is the radius. As
and R =17 cm = 0.17 m, then the voltage will be

The time is required to find to reach the voltage of 1500 V, so


So, 14 ms is required to reach the potential of 1500 V.