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Lena [83]
3 years ago
9

Which one of the following substances is a liquid fuel used in rocket engines?

Physics
2 answers:
natima [27]3 years ago
5 0

your answer is B. Ammonia

i just took the test

sergiy2304 [10]3 years ago
4 0
The answer is, "B", "Ammonia".
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An object is 3.0 cm from a concave mirror, with a focal length of 1.5 cm. Calculate the image distance. Remember to include your
Sunny_sXe [5.5K]

Answer:

Construct a quadrilateral ABCD, where

Construct a quadrilateral ABCD, whereAB = 4 cm, BC = 5 cm, CD = 6.5 cm and angle B = 105° and angle C = 80°

7 0
3 years ago
Your mom is making lunch which forces are acting on your mom
N76 [4]

The forces acting on your mom while cooking is Air resistance and the force of friction

<u>Explanation:</u>

<u>1. Air resistance:</u>

  • In simple words, Air resistance can be stated as the type of friction  between the air and the other materials.
  • In this scenario, there will be an air resistance and the air hits the mom while cooking via the doors or windows

<u>2. The force of friction:</u>

  • In simple words, friction can be stated as, the resistance that one surface or object encounters when moving over another.
  • While cooking the food mom would experience the friction since friction is the transfer of heat, and cooking is the process of receiving that heat.

7 0
3 years ago
Read 2 more answers
A wave has a wavelength of 9 mm and a frequency of 14 hertz. What is its speed?
lesantik [10]
Wavespeed = frequency x wavelength
= 14 x 9
= 126 mm/s
= 0.126 m/s
5 0
3 years ago
Charge A and charge B are 3.00 m apart, and charge A is +1.44 C and charge B is +3.10 C. Charge C is located between them at a c
Sidana [21]

Answer:

the distance from charge A to C is r₁₃= 1.216 m

Explanation:

following Coulomb's law , the force exerted by 2 point charges between themselves is:

F= k*q₁*q₂/r₁₂² , where q is charge , r is distance and 1 and 2 represents the charge A and charge B respectively , k=constant

since C ( denoted as 3) is at equilibrium

F₁₃=F₂₃

k*q₁*q₃/r₁₃²=k*q₂*q₃/r₂₃²

q₁/r₁₃²=q₂/r₂₃²

r₁₃²/q₁=r₂₃²/q₂

r₂₃=r₁₃*√(q₂/q₁)

since C is at rest and is co linear with A and B ( otherwise it would receive a net force in either vertical or horizontal direction) , we have

r₁₃+r₂₃=d=r₁₂

r₁₃+r₁₃*√(q₂/q₁)=d

r₁₃*(1+√(q₂/q₁))=d

r₁₃=d/(1+√(q₂/q₁))

replacing values

r₁₃=d/(1+√(q₂/q₁)) = 3.00 m/(1+√(3.10 C/1.44 C)) = 1.216 m

thus the distance from charge A to C is r₁₃= 1.216 m

7 0
3 years ago
An archery contestant
storchak [24]

Answer: A

Explanation:

8 0
3 years ago
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