penetrating electromagnetic radiation of a kind arising from the radioactive decay of atomic nuclei
The answer is: the rate of reaction is 850 g/min.
n(P₄O₁₀) = 1.5 mol; amount of product.
M(P₄O₁₀) = 283.9 g/mol; molar mass of phosphorus(V) oxide.
m(P₄O₁₀) = n(P₄O₁₀) · M(P₄O₁₀).
m(P₄O₁₀) = 1.5 mol · 283.9 g/mol.
m(P₄O₁₀) = 425.85 g in 30 seconds.
Make proportion: 425 g : 30 s = m(P₄O₁₀) : 60 s.
m(P₄O₁₀) = 850 g in 60 s.
Answer:
1.7 M
Explanation:
Given data:
Mass of AgNO₃ = 29.66 g
Volume of solution = 100 mL (100/1000 = 0.1 L)
Molarity of solution = ?
Solution;
Number of moles of AgNO₃:
Number of moles = mass/ molar mass
Number of moles = 29.66 g/ 169.87 g/mol
Number of moles = 0.17 mol
Molarity of solution:
Molarity = moles of solute / volume of solution in L
Molarity = 0.17 mol / 0.1 L
Molarity = 1.7 M
Convert the 48.7 grams into moles and then use the balanced equation to convert to moles of hydrogen gas. Then divide by avogadro's number<span />
