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2 years ago

What is the density of an object with mass of 60 g and a volume of 2cm3

Physics

1 answer:

Artemon [7]2 years ago

4 0

Answer:

D=mass /volume

=60/0.002

=30000

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Each color is visible light corresponds to a different?

AnnyKZ [126]

Wavelengths and frequecy

8 0

4 years ago

Read 2 more answers

a metal of length 15.04cm is heated until its temperature rises by 65°c. if its new length is 16.00m calculate its linear expans

spin [16.1K]

Answer:

ΔL = L0 C ΔT

We need to find C the constant of expansivity

C = ΔL / (L0 ΔT)

C = .96 / (15.04 * 65) = 9.82 * 10^-4 / deg C

5 0

2 years ago

Traveling at an average rateaverage rate of between 50 and 60 miles per hour for 4 to 7 hours select the best estimate for the d

borishaifa [10]

Answer:

best close estimate distance is 315 miles

Explanation:

given data

speed v1 = 50 miles per hour

speed v2 = 60 miles per hour

time t1 = 4 hr

time t2 = 7 hr

to find out

best estimate for the distance traveled

solution

we know lower end distance

distance = v1 × t1

distance = 50 × 4 = 200 miles

and

upper end distance

distance = v2 × t2

distance = 60 × 7 = 420 miles

so middle value distance is

v = 55 miles per hour and t = 5.5 hours

distance = v × t

distance = 55 × 5.5

distance = 302.5 miles

so best close estimate distance is 315 miles

3 0

3 years ago

EX 6-1 A ball is twirled on a 0.870 - m-long string with a constant speed of 3.36 m / s . Calculate the acceleration of the ball

Elina [12.6K]

Answer:

$a=12.97\ m/s^2$

Explanation:

Given that,

The length of a string, l = 0.87 m

Speed of the ball, v = 3.36 m/s

We need to find the acceleration of the ball. The acceleration acting on the ball is centripetal acceleration. It is given by :

$a=\dfrac{v^2}{r}\\\\a=\dfrac{(3.36)^2}{0.87}\\\\=12.97\ m/s^2$

So, the acceleration of the ball is $12.97\ m/s^2$ .

4 0

3 years ago

Water runs into a fountain, filling all the pipes, at a steady rate of 0.750 m3>s. (a) How fast will it shoot out of a hole 4

kati45 [8]

Answer:

velocity = 472 m/s

velocity = 52.4 m/s

Explanation:

given data

steady rate = 0.750 m³/s

diameter = 4.50 cm

solution

we use here flow rate formula that is

flow rate = Area × velocity .............1

0.750 = $\frac{\pi }{4}$ × (4.50× $10^{-2}$ )² × velocity

solve it we get

velocity = 472 m/s

and

when it 3 time diameter

put valuer in equation 1

0.750 = $\frac{\pi }{4}$ × 3 × (4.50× $10^{-2}$ )² × velocity

velocity = 52.4 m/s

5 0

3 years ago