Explanation:
(a) It is given that two-third of weight is over the drive wheels. So, mathematically, w = 
.
Hence, maximum force is expressed as follows.
Hence, the maximum acceleration is calculated as follows.
= 
= 6.53 
Hence, the maximum acceleration of the Porsche on a concrete surface where μs = 1 is 6.53 .
(b) Since, 30% of the power is lost in the drive train. So, the new power is 70% of 
.
That is, new power = 
Now, the expression for power in terms of force and velocity is as follows.
P = 
Therefore, speed of the Porsche at maximum power output is as follows.
= 
= 11.568 m/s
= 11.57 m/s
Therefore, speed of the Porsche at maximum power output is 11.57 m/s.
(c) The time taken will be calculated as follows.
time = 
= 
= 1.77 s
Therefore, the Porsche takes 1.77 sec until it reaches the maximum power output.
Renewable energy or a energy that can be used again
The process of arriving at a general conclusion based on the observation of specific examples is called inductive reasoning. It is a logical process where multiple premises are combined to obtain a conclusion. It is <span>used in applications that involve prediction and forecasting.</span>
Refer to the diagram shown below.
The force, F, is applied at 5 cm from the elbow.
For dynamic equilibrium, the sum of moments about the elbow is zero.
Take moments about the elbow.
(5 cm)*(F N) - (30 cm)*(250 N) = 0
F = (30*250)/5 = 1500 N
Answer: 1500 N
Answer:
n₁ = 3
Explanation:
The energy of the states in the hydrogen atom is explained by the Bohr model, the transitions heal when an electron passes from a state of higher energy to another of lower energy,
ΔE = 
- E₀ = - k²e² / 2m (1 / 
²2 - 1 / n₀²)
The energy of this transition is given by the Planck equation
E = h f = h c / λ
h c / λ = -k²e² / 2m (1 / no ²- 1 / no²)
1 / λ = Ry (1/ ² - 1 / n₀²)
Let's apply these equations to our case
λ = 821 nm = 821 10⁻⁹ m
E = h c / λ
E = 6.63 10⁻³⁴ 3 10⁸/821 10⁻⁹
E = 2.423 10⁻¹⁹ J
Now we can use the Bohr equation
Let's reduce to eV
E = 2,423 10⁻¹⁹ J (1eV / 1.6 10⁻¹⁹) = 1,514 eV
- E₀ = -13.606 (1 / ² - 1 / n₀²) [eV]
Let's look for the energy of some levels
n 
(eV) - E
(eV)
1 -13,606 E₂-E₁ = 10.20
2 -3.4015 E₃-E₂ = 1.89
3 -1.512 E₄- E₃ = 0.662
4 -0.850375
We see the lines of greatest energy for each possible series, the closest to our transition is n₁ = 3 in which a transition from infinity (n = inf) to this level has an energy of 1,512 eV that is very close to the given value
