Answer:
257.32
Explanation:
I jus worked it out on paper. Brainliest please?
Work formula:
![W = Fd\cos(\theta)](https://tex.z-dn.net/?f=W%20%3D%20Fd%5Ccos%28%5Ctheta%29)
F = 50N, d = 1.0 m
When you lift something straight up, the angle of the force is 90º
cos(90º) is 0, so there's no work done when you lift the microwave off the ground
![W = (50N)(1.0)(0) = 0](https://tex.z-dn.net/?f=W%20%3D%20%2850N%29%281.0%29%280%29%20%3D%200)
F = 50N, d = 1.0 m
When you push the microwave, the angle is 0º and cos(0º) is 1. So there is work done here:
![W = (50 N)(1.0m)(1)](https://tex.z-dn.net/?f=W%20%3D%20%2850%20N%29%281.0m%29%281%29)
![W = 50](https://tex.z-dn.net/?f=W%20%3D%2050)
total work = 50 joules
I got you b, V(final)^2=V(initial+2acceleration*displacement
So this turns to (0m/s)^2=(50m/s)^2+2(9.8)(d) so just flip it all around to isolate d so you get
-(50m/s)^2/2(9.8) = d so you get roughly 12.7555 meters up
It'll certainly seem like it, because the water will get cold. But cold is not a thing. Heat is. What actually happens is that heat from the water flow into the ice (and melts it).