Earlier, we stated Newton's first law as “A body at rest remains at rest or, if in motion, remains in motion at constant velocity unless acted on by a net external force.” It can also be stated as “Every body remains in its state of uniform motion in a straight line unless it is compelled to change that state by forces
For example-A stationary object with no outside force will not move. With no outside forces, a moving object will not stop. An astronaut who has their screwdriver knocked into space will see the screwdriver continue on at the same speed and direction forever.
KE = (1/2)·(mass)·(speed)²
It doesn't matter whether the object is in a car, on a boat,
falling, on a conveyor belt, or being carried by ants.
KE = (1/2)·(40 kg)·(2 m/s)²
KE = (20 kg)·(4 m²/s²)
KE = 80 kg-m²/s²
KE = 80 Joules
Answer:
It's terrifying, but a relief that you know your children isn't home alone.
Explanation:
Why, it's because sometimes you don't know what is going on in the daycare. The baby/ the child you gave birth to is in the hands of a random stranger. It's also a relief knowing that at least someone is taking care of your child, or hope to be. Instead of your child, no adult supervision or any people watching your child can result in death, injuries, and more since your child is alone.
Answer:
The index of refraction varies with frequency or color. Frequency does not change as light travels from one medium to another.
Explanation:
Answer:
(a) 2.542 cm
(b) 272.7°C
Explanation:
diameter, d = 2.540 cm
T1 = 20°C
α = 11 x 10^-6 /°C
(a) Let d' be the diameter.
T2 = 87°C
Use he formula for the areal expansion
A' = A ( 1 + βΔT)
where, β is the coefficient of areal expansion and ΔT is teh rise in temperature, A' be the area at high temperature and A be the area at low temperature.
β = 2 α = 2 x 11 x 106-6 = 22 x 10^-6 /°C
So,

D'^2 = 2.54^2 ( 1 + 22 x 10^-6 x 67)
D' = 2.542 cm
(b) Let the change in temperature is ΔT.
Use the formula for the volumetric expansion
ΔV = V x γ x ΔT
Where, γ = 3 x α = 3 x 11 x 10^-6 = 33 x 10^-6 /°C
0.9/100 = 33 x 10^-6 x ΔT
ΔT = 272.7°C