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sergij07 [2.7K]
2 years ago
5

Isocyanic acid, also known as Hydrogen cyanate, is a weak acid and a potentially toxic atmospheric pollutant. Write down the equ

ation for the dissociation of isocyanic acid in water. Explain the term conjugate base and state the correct conjugate base of isocyanic acid. Give a reason for your answer.
Chemistry
1 answer:
densk [106]2 years ago
8 0

The dissociation of isocyanic acid in water produces its conjugate base, C N- since it will accept a proton to form isocyanic acid.

<h3>What is a conjugate base?</h3>

A conjugate base is a substance which is formed from the loss of the hydrogen ion of an acid and which will act as a base by accepting a proton.

The dissociation of Isocyanic acid in water is given below:

HC N + H_2O \rightleftharpoons C N^{-} + H_3O^{+}

The conjugate base is C N- since it will accept a proton to form isocyanic acid.

Learn more about conjugate base at: brainly.com/question/22514615

#SPJ1

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An atom with 25 protons and 27 electrons has a charge of +<br><br> True<br><br> False??
sleet_krkn [62]

Answer:

Unless you mistyped the question, the answer should be 25+

6 0
3 years ago
A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,
choli [55]

Answer:

3.676 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have different values of V and T:

(V₁T₂) = (V₂T₁)

Knowing that:

V₁ = 3.5 L, T₁ = 25°C + 273 = 298 K,

V₂ = ??? L, T₂ = 40°C + 273 = 313 K,

Applying in the above equation

(V₁T₂) = (V₂T₁)

∴ V₂ = (V₁T₂)/(T₁) = (3.5 L)(313 K)/(298 K) = 3.676 L.

7 0
3 years ago
What are some substances that from ion-ion forces?
Anika [276]

Answer:

The three major types of intermolecular interactions are dipole–dipole interactions, London dispersion forces (these two are often referred to collectively as van der Waals forces), and hydrogen bonds.

6 0
3 years ago
What is the molarity of a solution that contains 148g NaOH in 4.00 L solution? a 0.925 M b 0.0253 M c 0.459 M d 1.363 M
Anton [14]

Answer:

M = 0,925

Explanation:

n= mass/Molecular Weight

n = 148g / 39,99 (g/mol)

n= 3,7mol

M= n/Volumen(L)

M= 3,7mol/4L

M=0,925

8 0
3 years ago
At a given temperature, the elementary reaction A − ⇀ ↽ − B , in the forward direction, is first order in A with a rate constant
ZanzabumX [31]

Answer:

0.24

Explanation:

We are given that

Rate constant for A=k=0.0180/s

Rate constant for  B,k'=0.0750/s

We have to find the value of equilibrium constant for the reaction

A\rightleftharpoons B

Equilibrium constant, for k=\frac{k}{k'}

Using the formula

k=\frac{0.0180}{0.0750}=0.24

Hence, the value of the equilibrium constant for the reaction

A\rightleftharpoons B at this temperature=0.24

4 0
3 years ago
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