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Zielflug [23.3K]
2 years ago
14

Which of the following are basic principles that apply to circuits? Choose the 2 correct answers from the choices below.

Physics
1 answer:
marta [7]2 years ago
5 0

The basic principles that apply to circuits is that electrons must receive energy from a source, and electrons transfer energy to perform some useful function.

<h3 /><h3>What is circuit?</h3>

Individual electronic components, like resistors, transistors, are connected by metallic wires or traces by which the electric current can flow to form a circuit design.

The basic principles that apply to circuits will be;

1. Electrons must receive energy from a source.

2. Electrons transfer energy to perform some useful function.

Hence, option 1 and 2 are correct.

To learn more about the circuit, refer to the link;

brainly.com/question/21505732

#SPJ1

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The “Big Bang” is an example of what type of scientific statement? A. A law B.a hypothesis C. A theory D. An equation
Ugo [173]

Answer:

theory

Explanation:

that's why it's called the Big Bang Theory

6 0
2 years ago
Read 2 more answers
A laser is placed at the point $(3,5)$. The laser beam travels in a straight line. Larry wants the beam to hit and bounce off th
Black_prince [1.1K]

Answer:

4units

Explanation:

To calculate the total distance the beam will travel along this path, you will use the formula for calculating the distance between two coordinates expressed as;

D = √(x2-x1)²+(y2-y1)²

Given the coordinate points

(3,5) and (7,5)

Substitute

D = √(7-3)²+(5-5)²

D = √(7-3)²+0²

D = √4²

D = √16

D = 4

Hence the total distance the beam will travel along this path is 4units

6 0
3 years ago
While flying at an altitude of 5.75 km, you look out the window at various objects on the ground. If your ability to distinguish
Bingel [31]

Answer:

the smallest separation between two objects is 0.8067 m

Explanation:

Given the data in the question;

Altitude h = 5.75 km = 5750 m

Diameter D = 4.0 mm = 0.004 m

λ = 460 nm = 4.6 × 10⁻⁷ m

Now, Using Rayleigh criterion for Airy disks resolution.

we know that, Minimum angular separation for resolving two points is;

θ = 1.22λ / D

so we substitute

θ = (1.22 × 4.6 × 10⁻⁷)  / 0.004

θ = 5.612 × 10⁻⁷ / 0.004

θ = 1.403 × 10⁻⁴ rad  

so minimum separation d_{min =  θh

so we substitute

d_{min = (1.403 × 10⁻⁴) × 5750 m

d_{min = 0.8067 m

Therefore, the smallest separation between two objects is 0.8067 m

6 0
3 years ago
A 36.0 kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 130
konstantin123 [22]

Answer:

(a) W = 650J

(b) Wf = 529.2J

(c) W = 0J

(d) W = 0J

(e) ΔK = 120.8J

(f) v2 = 2.58 m/s

Explanation:

(a) In order to find the work done by the applied force you use the following formula:

W=Fd      (1)

F: applied force = 130N

d: distance = 5.0m

W=(130N)(5.0m)=650J

The work done by the applied force is 650J

(b) The increase in the internal energy of the box-floor system is given by the work done of the friction force, which is calculated as follow:

W_f=F_fd=\mu Mgd       (2)

μ: coefficient of friction = 0.300

M: mass of the box = 36.0kg

g: gravitational constant = 9.8 m/s^2

W_f=(0.300)(36.0kg)(9.8m/s^2)(5.0m)=529.2J

The increase in the internal energy is 529.2J

(c) The normal force does not make work on the box because the normal force is perpendicular to the motion of the box.

W = 0J

(d) The same for the work done by the normal force. The work done by the gravitational force is zero because the motion of the box is perpendicular o the direction of the gravitational force.

(e) The change in the kinetic energy is given by the net work on the box. You use the following formula:

\Delta K=W_T         (3)

You calculate the total work:

W_T=Fd-F_fd=(F-F_f)d     (4)

F: applied force = 130N

Ff: friction force

d: distance = 5.00m

The friction force is:

F_f=(0.300)(36.0kg)(9.8m/s^2)=105.84N

Next, you replace the values of all parameters in the equation (4):

W_T=(130N-105.84N)(5.00m)=120.80J

\Delta K=120.80J

The change in the kinetic energy of the box is 120.8J

(e) The final speed of the box is calculated by using the equation (3):

W_T=\frac{1}{2}M(v_2^2-v_1^2)       (5)

v2: final speed of the box

v1: initial speed of the box = 0 m/s

You solve the equation (5) for v2:

v_2 = \sqrt{\frac{2W_T}{M}}=\sqrt{\frac{2(120.8J)}{36.0kg}}=2.58\frac{m}{s}

The final speed of the box is 2.58m/s

5 0
3 years ago
Please help me with this problem for physics !
Westkost [7]

Answer:

2 m/s²

Explanation:

velocity =

\frac{20 - 0}{10}

20/10 = 2

4 0
3 years ago
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