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gogolik [260]
3 years ago
6

The speed of sound in air is 345 m/s. A tuning fork vibrates above the open end of a sound resonance tube. If sound waves have w

avelengths 63-cm in the tube, what is the frequency (in Hertz) of the tuning fork? Never include units with a numerical answer.
Physics
1 answer:
Delvig [45]3 years ago
6 0

To develop this problem it is necessary to apply the concept of Frequency based on speed and wavelength.

According to the definition the frequency can be expressed as

f = \frac{v}{\lambda}

Where,

v = Velocity

\lambda = Wavelength

Our value are given by,

v = 345m/s

\lambda = 63cm

Replacing

f = \frac{345}{0.63}

f = 547.61Hz

Therefore the frequency of the tuning fork is 547.61Hz

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Answer:

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Explanation:

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under relativistic effect, the new mass M will be

M = M_{0}/ \sqrt{1 - \beta ^{2}  }

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The new momentum will therefore be

==> M_{0}V/ \sqrt{1 - \beta ^{2}  }

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the equation reduces to

1.75 = 1/ \sqrt{1 - \beta ^{2}  }

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3 years ago
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