Answer:
= 1.9792 × 10^10
Significant Figures= 5
Explanation:
Look at the attachment below
Hope this helps (:
Work = Force * distance
Force = 70 N
Work = 3500 J
3500 = 70d
d = 3500/70 = 50 m
Since my givens are x = .550m [Vsub0] = unknown
[Asubx] = =9.80
[Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0]
[Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0])
Vsubx is the final velocity, which at the max height is 0, and Xsub0 is just 0 as that's where it starts so I just plug the rest in
0^2 = [Vsub0x]^2 + 2[-9.80]*(.550)
0 = [Vsub0x]^2 -10.78
10.78 = [Vsub0x]^2
Sqrt(10.78) = 3.28 m/s
That will depend on the coefficient of friction between the sliding surfaces, and also on Zak's weight. We don't have any of that information.
The kinetic energy of an object is given by:

where m is the mass of the object and v its velocity.
The car in this problem has a mass of m=600 kg and a velocity of v=10 m/s, therefore if we put these numbers into the equation, we find the kinetic energy of the car: